请问在SQL中怎样生成这样的结果

Question

原始数据

原始数据

最终需要胡结果

Answer 1

USE [YTRMV6]
GO

/****** Object:  Table [dbo].[示向度误差纠正表]    Script Date: 04/17/2015 11:46:03 ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE TABLE [dbo].[示向度误差纠正表](
[ID] [bigint] IDENTITY(1,1) NOT NULL,
[中心频率] [decimal](18, 0) NOT NULL,
[示向度] [bigint] NULL,
[误差值] [bigint] NULL,
 CONSTRAINT [PK_示向度误差纠正表] PRIMARY KEY CLUSTERED 
(
[ID] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

ALTER TABLE [dbo].[示向度误差纠正表] ADD  CONSTRAINT [DF_示向度误差纠正表_中心频率]  DEFAULT ((0)) FOR [中心频率]
GO

ALTER TABLE [dbo].[示向度误差纠正表] ADD  CONSTRAINT [DF_示向度误差纠正表_示向度]  DEFAULT ((0)) FOR [示向度]
GO

ALTER TABLE [dbo].[示向度误差纠正表] ADD  CONSTRAINT [DF_示向度误差纠正表_误差值]  DEFAULT ((0)) FOR [误差值]
GO

Answer 2

用pivot，这个有点复杂，详情查询msdn.microsoft.com。你自己学会写比较好，所以我就不帮你写了。

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