DataGridComboBoxColumn 根据DataGrid中的数据显示问题

Question

我在DataGrid显示员工信息，想在表格里实现呈现和修改数据。

员工工种用DataGridComboBoxColumn来显示（工种用了一个数据源来填充）。

怎么样才能让DataGridComboBoxColumn 列根据DataGrid中的工种Id显示正确的值呢？

Answer 1

你好！

DataGrid 是 Framework 1.1 时的控件，Framework 2.0 以及后使用 DataGridView 控件代替原来的 DataGrid 控件。

在 DataGridView 控件上述问题使用默认绑定就可以了，如下代码：

public partial class Sample : Form
{
    public Sample()
    {
        InitializeDemo();
    }

    void InitializeDemo()
    {
        var categories = new List<EmployeeCategory>
        {
            new EmployeeCategory{ EmployeeCategoryId = 1, Name = "Category1"},
            new EmployeeCategory{ EmployeeCategoryId = 2, Name = "Category2"}
        };

        var employees = new List<Employee> 
        { 
            new Employee{ EmployeeId =1, Name = "Employee1", Category = 1 },
            new Employee{ EmployeeId =2, Name = "Employee2", Category = 2 }
        };

        var col1 = new DataGridViewTextBoxColumn()
        {
            HeaderText = "EmployeeId",
            DataPropertyName = "EmployeeId"
        };
        var col2 = new DataGridViewTextBoxColumn()
        {
            HeaderText = "Name",
            DataPropertyName = "Name"
        };
        var col3 = new DataGridViewComboBoxColumn()
        {
            HeaderText = "Category",
            DataPropertyName = "Category",
            DisplayMember = "Name",
            ValueMember = "EmployeeCategoryId",
            DataSource = categories
        }; 

        var dg = new DataGridView { AutoGenerateColumns = false, Dock = DockStyle.Fill };

        dg.Columns.Add(col1);
        dg.Columns.Add(col2);
        dg.Columns.Add(col3);

        dg.DataSource = employees;

        this.Controls.Add(dg);
    }

    public class Employee
    {
        public int EmployeeId { get; set; }
        public string Name { get; set; }
        public int Category { get; set; }
    }

    public class EmployeeCategory
    {
        public int EmployeeCategoryId { get; set; }
        public string Name { get; set; }
    }

    public class DemoData
    {
        public string Name { get; set; }
        public decimal Value { get; set; }
    }
}

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