有关Ibuffer^ 转 byte* 或者void*的求助（C++）

Question

请问Ibuffer^ 转 byte* 或者void*该怎么转呢？

auto openPicker = ref new FileOpenPicker();
	openPicker->ViewMode = PickerViewMode::List;
    openPicker->SuggestedStartLocation = PickerLocationId::DocumentsLibrary;
    openPicker->FileTypeFilter->Append(".pdf");

	task<StorageFile^>(openPicker->PickSingleFileAsync()).then([this](StorageFile^ openedFile)
	{
		if (openedFile != nullptr)
		{
			
			task<IBuffer^>(FileIO::ReadBufferAsync(openedFile)).then([this](IBuffer^ buffer)
			{
	
			});
		}
	});

我只是想实现win32的fopen功能， FILE* m_iFileRead = fopen(lpszPathName, "rb");

希望高手们指点一二，谢谢！

Answer 1

通过摸索得到下面的方法，不知道正不正确。现分享出来，如有错误，欢迎指正！

DataReader^ dataReader = DataReader::FromBuffer(buffer);
				Array<unsigned char,1>^ myarray =ref new Array<unsigned char,1>(buffer->Length);
				dataReader->ReadBytes(myarray);

unsigned char * ch = myarray->begin();
				unsigned char * ch2 = myarray->Data;

Answer 2

没错，我们可以通过 DataReader/DataWriter 来在 IBuffer 和 byte*, char[], string间转换。 官方的File Access sample 里面就用到了这个方式去将string转成IBuffer： File access sample

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Bob Bao [MSFT]
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