c++编程

Question

     怎样在小于5000的自然数中找到能被11整除且各位数字加起来等于13的数字。。

Answer 1

#include "stdafx.h"
#include <iostream>
using namespace std;
#define MAX_VALUE	(5000)
#define NUM_VALUE	(11)
#define SUM_VALUE	(13)
bool IsValidNumber(int nValue)
{
	int sum = 0;
	while(nValue)
	{
		sum += (nValue % 10);
		nValue /= 10;
	}
	return (sum == SUM_VALUE);
}
int main(int argc, char* argv[])
{
	for(int i = NUM_VALUE; i < MAX_VALUE; i += NUM_VALUE)
	{
		if(IsValidNumber(i))
		{
			cout<<i<<endl;
		}
	}
	return 0;
}

期待有更好的算法。

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Visual C++ enthusiast, like network programming and driver development. At present is being engaged in the WinCE/Windows Mobile platform embedded development.

Answer 2

  谢了。。。

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雷神