请问如何使用C++代码打开"开始"->"设置"界面?

Question

我想实现一个功能,当点击某个按钮时,程序打开"开始"->"设置"的界面.
我原来的想法是使用ShellExecuteEx函数调用\Windows\ctlpnl.exe来显示,但是不起作用,请问还有什么更好的方法吗?
我使用的开发语言是C++,非MFC
谢谢大家

Answer 1

用CreateProcess来打开ctlpnl.exe程序，
http://social.msdn.microsoft.com/Forums/en-US/windowsmobiledev/thread/c9e65358-8efb-4e29-871e-236427a71744/

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Answer 2

用CreateProcess来打开ctlpnl.exe程序，
http://social.msdn.microsoft.com/Forums/en-US/windowsmobiledev/thread/c9e65358-8efb-4e29-871e-236427a71744/

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感谢版主,你说的这个我知道,但是我想要打开设置界面,而不是具体的某个设置项,即用户点击"开始"->"设置"的那个界面

Answer 3

ctlpnl.exe典型的需要一个cpl来设置相应的设置界面。

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