如何序列化CRgn对象？

Question

因为程序需要，我要把CRgn对象存储到硬盘上。但是CArchive不支持这种格式对象。因此在这里求教各位大侠了！

Answer 1

MSDN上有讲到如何序列化
Five main steps are required to make a class serializable. They are listed below and explained in the following sections:

1. Deriving your class from CObject (or from some class derived from CObject).

2. Overriding the Serialize member function.

3. Using the DECLARE_SERIAL macro in the class declaration.

4. Defining a constructor that takes no arguments.

5. Using the IMPLEMENT_SERIAL macro in the implementation file for your class.

If you call Serialize directly rather than through the >> and << operators of <link keywords="9E950D23-B874-456E-AE4B-FE00781A7699" tabIndex="0" />, the last three steps are not required for serialization.

CRgn派生自CGdiObject，CGdiObject派生自CObject类，重载Serialize函数。

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Answer 2

CRgn不支持序列化。不过你可以序列化创建了这个对象的步骤，比如如果是line to出来的结果的话，把起始点和线宽记录下来。

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Answer 3

这个大概可以吧：

DWORD GetRegionData( HRGN hRgn, // handle to region
DWORD dwCount, // size of region data buffer
LPRGNDATA lpRgnData // region data buffer );

HRGN ExtCreateRegion( CONST XFORM *lpXform, // transformation data
DWORD nCount, // size of region data
CONST RGNDATA *lpRgnData // region data buffer );

Answer 4

这个只对CreateFromRect的有用吧？CreateFromPath的呢？

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Answer 5

没试过但是，这是RGNDATA的定义

typedef struct _RGNDATAHEADER {
    DWORD   dwSize;
    DWORD   iType;
    DWORD   nCount;
    DWORD   nRgnSize;
    RECT    rcBound;
} RGNDATAHEADER, *PRGNDATAHEADER;

typedef struct _RGNDATA {
    RGNDATAHEADER   rdh;
    char            Buffer[1];
} RGNDATA, *PRGNDATA, NEAR *NPRGNDATA, FAR *LPRGNDATA;

所以，RGNDATA是变长的结构，应该不仅仅支持RECT。GetRegionData函数的参数dwCount是字节，不是RGNDATA数组的大小。

Answer 6

那个butter[1]是Rect数组的首地址……

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Answer 7

我看了msdn，你说的没错，确实buffer是RECT数组。但是我试了一下，用path画了一个大约100*100大小的三角形。
最后得到的RGNDATA由99个RECT组成，也就是一行一个RECT。

Answer 8

的确是一行一个rect的，这是用网格来逼近直线，在不同的计算机上可能有不同的结果。如果光是序列化rgndata的话当然可以这么做，但是如果用来还原Path的话未必精确。

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Answer 9

不是序列化rgn吗。要序列化path用metafile。