string 解析成xml并取得值

Question

我访问一个webservice并取得一个string 类型的返回值，返回的是xml如：
<?xml version="1.0" encoding="utf-8" ?>
<sysSetDataFile>
  <setBit>1</setBit>
  <netConn mode="DHCP" />
  <sigOutSet mode="4" value="17" />
  <onOffTime group="1" on_time1="00:00:00" off_time1="23:55:00" week1="127" />
  <osdLangSet value="0" />
</sysSetDataFile>
现在我要解析这个string 成xml，并取得其中的值，比如 onOffTime xia 的off_time1,怎么取呢？
谢谢各位大侠。

Answer 1

请给一个详细的代码例子

Answer 2

你用这个字符串创建一个XML文件，从XML文件中读取你要的节点值

读取XML参照这里
http://hi.baidu.com/onlyafar/blog/item/8eb1de2a0bfab192023bf610.html

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努力+方法=成功

Answer 3

using System;
using System.Collections;
using System.Configuration;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;
using System.Xml;

public partial class Default12 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        string inputXML = 
            "<?xml version=\"1.0\" encoding=\"utf-8\" ?>"
            + "<sysSetDataFile>"
            + "<setBit>1</setBit>"
            + "<netConn mode=\"DHCP\" />"
            + "<sigOutSet mode=\"4\" value=\"17\" />"
            + "<onOffTime group=\"1\" on_time1=\"00:00:00\" off_time1=\"23:55:00\" week1=\"127\" />"
            + "<onOffTime group=\"2\" on_time1=\"00:00:00\" off_time1=\"23:55:00\" week1=\"128\" />"
            + "<onOffTime group=\"3\" on_time1=\"00:00:00\" off_time1=\"23:55:00\" week1=\"129\" />"
            + "<osdLangSet value=\"0\" />"
            + "</sysSetDataFile>";

        XmlDocument doc = new XmlDocument();

        doc.LoadXml(inputXML);

        this.PrintAttribute(doc.ChildNodes);
    }

    private void PrintAttribute(XmlNodeList nodes)
    {
        foreach (XmlNode node in nodes)
        {
            if (node.Name == "onOffTime")
            {
                Response.Write(String.Format("group:{0}&nbsp;&nbsp;on_time1:{1}&nbsp;&nbsp;week1:{2}<br />"
                    , node.Attributes["group"].Value
                    , node.Attributes["on_time1"].Value
                    , node.Attributes["week1"].Value));
            }

            this.PrintAttribute(node.ChildNodes); // 递归
        }
    }
}

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知识改变命运，奋斗成就人生!

Answer 4

private static void TestXml()
        {
            string xml = @"<?xml version=""1.0"" encoding=""utf-8"" ?>
<sysSetDataFile>
  <setBit>1</setBit>
  <netConn mode=""DHCP"" />
  <sigOutSet mode=""4"" value=""17"" />
  <onOffTime group=""1"" on_time1=""00:00:00"" off_time1=""23:55:00"" week1=""127"" />
  <osdLangSet value=""0"" />
</sysSetDataFile>";
            XmlDocument dom = new XmlDocument();
            dom.LoadXml(xml);
            Console.WriteLine(dom.DocumentElement.SelectSingleNode("onOffTime/@off_time1").Value);
        }

楼主可以去了解下Xpath 借助XmlDocument类或者XPathDocument类就可以读取了

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Wenn ich dich hab’,gibt es nichts, was unerträglich ist.坚持不懈！My blog~~~

Answer 5

using System.Xml.Linq;
这是c#3.0 
protected void Page_Load(object sender, EventArgs e)
        {

            string xml= "<?xml version=\"1.0\" encoding=\"utf-8\" ?>"
              + "<sysSetDataFile>"
              + "<setBit>1</setBit>"
              + "<netConn mode=\"DHCP\" />"
              + "<sigOutSet mode=\"4\" value=\"17\" />"
              + "<onOffTime group=\"1\" on_time1=\"00:00:00\" off_time1=\"23:55:00\" week1=\"127\" />"
             + "<osdLangSet value=\"0\" />"
              + "</sysSetDataFile>";
            XDocument xd = XDocument.Parse(xml);
       string[] atts =( from x in xd.Element("sysSetDataFile").Elements("onOffTime")
                          select x.Attribute("off_time1").Value).ToArray();
         foreach (string att in atts )
            Response.Write(att);
        }

Answer 6

也可以用xmlreader~具体看msdn