skydrive上传提示主体无效，包含多个boundary

Question

代码如下：

String uploadUrl = "https://apis.live.net/v5.0/me/skydrive/files?overwrite=false&access_token=";

FileOpenPicker picker = new FileOpenPicker();
            picker.FileTypeFilter.Add("*");
            StorageFile file = await picker.PickSingleFileAsync();
            int indexOfUploadfileName = file.Path.LastIndexOf("\\");
            string fileName = file.Path.Substring(indexOfUploadfileName + 1);
            IRandomAccessStream readStream = await file.OpenAsync(FileAccessMode.Read);
            Stream stream = readStream.AsStream();
            MultipartFormDataContent form = new MultipartFormDataContent();
            StreamContent streamContent = new StreamContent(stream, (int)readStream.Size);
            streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
            {
                FileName = "\"" + fileName + "\"",
                Name = "\"file\""
               
            };
            streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
            form.Add(streamContent, "file");

Uri uri = new Uri(uploadUrl+access_token);

            try
            {
                HttpResponseMessage response = await httpClient.PostAsync(uri, form);
            }
            catch (Exception ex)
            {
                string x = ex.Message;
            }

Answer 1

{
   "error": {
      "code": "request_body_invalid",
      "message": "The request entity body for multipart form-data POST contains multiple boundaries. Only a single boundary value is permitted."
   }
}

Answer 2

我就创建一个MultipartFormDataContent实例，其他的全注释掉，怎么还是提示包含多个boundary？

Answer 3

FileOpenPicker picker = new FileOpenPicker();
            picker.FileTypeFilter.Add("*");
            StorageFile file = await picker.PickSingleFileAsync();
            int indexOfUploadfileName = file.Path.LastIndexOf("\\");
            string fileName = file.Path.Substring(indexOfUploadfileName + 1);
            IRandomAccessStream readStream = await file.OpenAsync(FileAccessMode.Read);
            Stream stream = readStream.AsStream();

            StreamContent streamContent = new StreamContent(stream, (int)readStream.Size);

            Uri uri = new Uri(uploadUrl +file.Name+ "?access_token=" + access_token);
           
            try
            {
                HttpResponseMessage response = await httpClient.PutAsync(uri, streamContent);
                string res =await response.Content.ReadAsStringAsync();
               
            }
            catch (Exception ex)
            {
                string x = ex.Message;
            }

用put实现了 之前走了弯路