C编程

Question

• 输出1到4这四个数字所能组成的互不相同且无重复数字的三位数

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雷神

Answer 1

#include <stdio.h>

void main()

{

int a[4]={1,2,3,4};

for(int i=0; i<4; i++)

for(int j=0; j<4; j++)

{ if (j==i) continue;

for(int k=0; k<4; k++)

{ if ((k==j)||(k==i)) continue;

printf("%d%d%d\n",*(a+i),*(a+j),*(a+k));}}}

Answer 2

#include "stdafx.h"
#include <iostream>
using namespace std;
int _tmain(int argc, TCHAR* argv[], TCHAR* envp[])
{
	for(int i = 1; i != 5; ++i)
	{
		for(int j = 1; j != 5; ++j)
		{
			for(int k = 1; k != 5; ++k)
			{
				if((i != j) && (i != k) && (j != k))
				{
					cout<<i<<j<<k<<endl;
				}
			}
		}
	}
	return 0;
}

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Visual C++ enthusiast, like network programming and driver development. At present is being engaged in the WinCE/Windows Mobile platform embedded development.

Answer 3

#include <iostream>

using namespace std;

void main()
{
	for(int i=1; i<5; i++)
	{
		for(int j=1; j<5; j++)
		{
			if(i==j)
				continue;
			for(int k=1; k<5; k++)
			{
				if(i==k || j==k)
					continue;

				cout<<i<<j<<k<<endl;
			}
		}
	}
	system("pause");
}