strtok报错

Question

char *str1="I am very happy,nprogramme";
char *token;
token = strtok(str1,",");

Answer 1

char *str1="I am very happy,nprogramme";
修改为

char str1[] = "I am very happy,nprogramme";

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Visual C++ enthusiast, like network programming and driver development. At present is being engaged in the WinCE/Windows Mobile platform embedded development.

Answer 2

Hi Hoony,

按VsualEleven的建议去改，应该是会解决您的问题的。

这是因为strtok()本身原因,这个函数会将被切割函数中出现切割字符的位置改写为'\0'。也就是函数本身会去改写它的第一参数

而
char *p=“aaaaaaaa”； //这样定义的字符串被存放在文字常量区，也就是字符串本身是一个常量，一般情况下不允许修改
char a[]=“aaaaaaaa”； //这种情况下字符串在栈区，可以修改

 

如果您的问题解决了，请把有用的回答标记为答案，

谢谢，

Lucy

 

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Lucy Liu [MSFT]
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