32位浮点数用BitConverter.GetBytes和StringBuilder得到十六进制数并格式化成8个十六进制字条

Question

Dim f As Single = 25.1F
        Dim b As Byte() = BitConverter.GetBytes(f)
        Dim sb As New StringBuilder()
        For Each by As Byte In b
            sb.Append(by.ToString("X"))
        Next
        这样sb="CDCCC841"    为有效8个字符的32位十六进制浮点数。但当f=100时得到“0042C8”,于是我认为第一个字符应该是“00”，第二个字符也应该是“00”，这样得到的结果是我想要的“000042C8”。请教如何格式化才能得到这样的结果呢？

Answer 1

你好,

可以把循环反一下。像这样：

Dim f As Single = 25.1F
         Dim b  As Byte() = BitConverter.GetBytes(f)
         Dim sb  As New StringBuilder()
         For i As Integer = b.Length - 1 To 0 Step -1
     sb.Append(b(i).ToString("X"))
 Next

Best regards,

Cole Wu

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Answer 2

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