Denemedim ama şöyle bir yöntem buldum
using Microsoft.VisualBasic;
using System;
using System.Collections;
using System.Collections.Generic;
using System.Data;
using System.Diagnostics;
using System.IO;
using System.Net;
using System.Text;
public class Form1
{
private void Form1_Load(System.Object sender, System.EventArgs e)
{
PostToImgur("d:\\10.jpg", "6e8590ecca2b620de00d15f00bd091d8");
}
public void PostToImgur(string FileName, string API_KEY)
{
byte[] imageData = null;
FileStream fs = File.OpenRead(FileName);
imageData = new byte[fs.Length + 1];
fs.Read(imageData, 0, imageData.Length);
fs.Close();
const int MAX_URI_LENGTH = 32766;
string base64img = System.Convert.ToBase64String(imageData);
StringBuilder sb = new StringBuilder();
int i = 0;
while (i < base64img.Length)
{
sb.Append(Uri.EscapeDataString(base64img.Substring(i, Math.Min(MAX_URI_LENGTH, base64img.Length - i))));
i += MAX_URI_LENGTH;
}
string uploadRequestString = "image=" + sb.ToString() + "&key=" + API_KEY;
HttpWebRequest webReq = (HttpWebRequest)WebRequest.Create("http://api.imgur.com/2/upload");
webReq.Method = "POST";
webReq.ContentType = "application/x-www-form-urlencoded";
webReq.ServicePoint.Expect100Continue = false;
StreamWriter sw = new StreamWriter(webReq.GetRequestStream());
sw.Write(uploadRequestString);
sw.Close();
WebResponse response = webReq.GetResponse();
Stream responseStream = response.GetResponseStream();
StreamReader responseReader = new StreamReader(responseStream);
string responseString = responseReader.ReadToEnd();
//gönderdiğin imajın url'sini almak için
TextBox1.Text = responseString;
}
public Form1()
{
Load += Form1_Load;
}
}
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