Descubri como fazer , e pra quem tiver os mesmos problemas que eu eis a solução
E so colocar o codigo :
<script type="text/javascript" src="http://www.google.com/jsapi"></script>
<script type="text/javascript">
// Load jQuery
google.load("jquery", "1.2.6");
</script>
<script type="text/javascript">
$(function(){
//initialize menus
var menuRows = $("[id$='QuickLaunchMenu'] > tbody > tr");
var menuHd = menuRows.filter("[id!='']:has(+tr[id=''])");
//set img path for when submenu is hidden
var closedImg = "/_layouts/images/Menu1.gif";
//set img path for when submenu is visible
var openedImg = "/_layouts/images/ptclose.gif";
var cssInit = {
"background-image": "url('"+closedImg+"')",
"background-repeat": "no-repeat",
"background-position": "100% 50%"
}
var cssClosed = {"background-image": "url('"+closedImg+"')"}
var cssOpen = {"background-image": "url('"+openedImg+"')"}
//hide submenus
menuRows.filter("[id='']").hide();
//apply initial inline style to menu headers
menuHd.find("td:last").css(cssInit);
menuHd.click(function () {
var styleElm = $(this).find("td:last")
var nextTR = $(this).next("tr[id='']");
if (nextTR.is(':visible')) {
nextTR.hide();
styleElm.css(cssClosed);
} else {
nextTR.show();
styleElm.css(cssOpen);
}
});
});
</script>
e na chamada dos links tem de colocar javascript:void(0);
