# Calculate absolutely X coordinate child shape of GroupShape

### Question

• Sorry for my English :)

I try get absolutely x coordinate child shape (Freeform 39) from GroupShape

My calculation: 4637017 (GroupShape X) + 5863712 (target ChildShape) = 10500729, but that calculation is incorrect, because when I added separate shape with this X (10500729) coordinate I see their located are different.

How properly to calculate absoulutely X coordinate of child shape?

mercredi 18 avril 2018 12:24

### Réponses

• I solved this task. All right, if we wanna to calculate absolutely position child shape on the slide to do that we can use following formula:

absChildShapeOffset,x(y) =  childShapeOffset,x(y) + groupShapeOffset,x(y) - childShapeOffset,x(y)

samedi 5 mai 2018 12:26

### Toutes les réponses

• First, I want to confirm with you that for which Office Application you are developing this code?

Then try to provide your code.

We will try to make a test with it and try to find the issue.

You can also try to post the picture of the actual output and desired output.

I will try to find a way to correctly calculate the coordinate value.

Regards

Deepak

MSDN Community Support
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jeudi 19 avril 2018 06:04

• Actual output (xml)

```<?xml version="1.0" encoding="UTF-8"?>
<p:sld xmlns:p="http://schemas.openxmlformats.org/presentationml/2006/main" xmlns:a="http://schemas.openxmlformats.org/drawingml/2006/main" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships">
<p:cSld>
<p:spTree>
<p:nvGrpSpPr>
<p:cNvPr id="1" name="" />
<p:cNvGrpSpPr />
<p:nvPr />
</p:nvGrpSpPr>
<p:grpSpPr>
<a:xfrm>
<a:off x="0" y="0" />
<a:ext cx="0" cy="0" />
<a:chOff x="0" y="0" />
<a:chExt cx="0" cy="0" />
</a:xfrm>
</p:grpSpPr>
<p:grpSp>
<p:nvGrpSpPr>
<p:cNvPr id="6" name="Group 50">
<a:extLst>
<a:ext uri="{FF2B5EF4-FFF2-40B4-BE49-F238E27FC236}">
<a16:creationId xmlns:a16="http://schemas.microsoft.com/office/drawing/2014/main" id="{8DB05407-77D7-499B-B344-9B1BCE58BF6F}" />
</a:ext>
</a:extLst>
</p:cNvPr>
<p:cNvGrpSpPr />
<p:nvPr />
</p:nvGrpSpPr>
<p:grpSpPr>
<a:xfrm>
<a:off x="1436819" y="1929700" />
<a:ext cx="1168676" cy="579718" />
<a:chOff x="563225" y="1336529" />
<a:chExt cx="1126054" cy="861088" />
</a:xfrm>
</p:grpSpPr>
<p:sp>
<p:nvSpPr>
<p:cNvPr id="7" name="Freeform 51">
<a:extLst>
<a:ext uri="{FF2B5EF4-FFF2-40B4-BE49-F238E27FC236}">
<a16:creationId xmlns:a16="http://schemas.microsoft.com/office/drawing/2014/main" id="{17BEC6F3-ACB3-4652-B0FE-0485FC5BC5F3}" />
</a:ext>
</a:extLst>
</p:cNvPr>
<p:cNvSpPr />
<p:nvPr />
</p:nvSpPr>
<p:spPr>
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<a:rect l="l" t="t" r="r" b="b" />
<a:pathLst>
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<a:moveTo>
<a:pt x="0" y="502939" />
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<a:lnTo>
<a:pt x="130628" y="502939" />
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<a:lnTo>
<a:pt x="130628" y="777098" />
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<a:lnTo>
<a:pt x="0" y="777098" />
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<a:close />
<a:moveTo>
<a:pt x="186190" y="292125" />
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<a:lnTo>
<a:pt x="316818" y="292125" />
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<a:lnTo>
<a:pt x="316818" y="777098" />
</a:lnTo>
<a:lnTo>
<a:pt x="186190" y="777098" />
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<a:close />
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<a:lnTo>
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<a:lnTo>
<a:pt x="372380" y="777098" />
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<a:lnTo>
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<a:lnTo>
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<a:close />
</a:path>
</a:pathLst>
</a:custGeom>
<a:solidFill>
<a:srgbClr val="96B2C4" />
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<a:ln>
<a:noFill />
</a:ln>
</p:spPr>
<p:style>
<a:lnRef idx="2">
<a:schemeClr val="accent1">
</a:schemeClr>
</a:lnRef>
<a:fillRef idx="1">
<a:schemeClr val="accent1" />
</a:fillRef>
<a:effectRef idx="0">
<a:schemeClr val="accent1" />
</a:effectRef>
<a:fontRef idx="minor">
<a:schemeClr val="lt1" />
</a:fontRef>
</p:style>
<p:txBody>
<a:bodyPr wrap="square" rtlCol="0" anchor="ctr">
<a:noAutofit />
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<a:lstStyle />
<a:p>
<a:pPr algn="ctr" />
<a:endParaRPr lang="en-US" sz="1400" dirty="0">
<a:solidFill>
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</p:sp>
<p:sp>
<p:nvSpPr>
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<a:ext uri="{FF2B5EF4-FFF2-40B4-BE49-F238E27FC236}">
<a16:creationId xmlns:a16="http://schemas.microsoft.com/office/drawing/2014/main" id="{D4073F8C-802F-409F-9527-6BE9826306EF}" />
</a:ext>
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<p:cNvSpPr />
<p:nvPr />
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<p:spPr>
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<a:custGeom>
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<a:lstStyle />
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<a:rPr lang="en-US" dirty="0" err="1" />
<a:t>myText</a:t>
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</p:sp>
</p:spTree>
<p:extLst>
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<p14:creationId xmlns:p14="http://schemas.microsoft.com/office/powerpoint/2010/main" val="2051546456" />
</p:ext>
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</p:cSld>
<p:clrMapOvr>
<a:masterClrMapping />
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</p:sld>```
actual output (picture)

Desired output

As you see to achieve this I need get absolutely X coordinate of circle element who is in group object, then set that value for my textBox (Text).

jeudi 19 avril 2018 21:34
• I use PowerPoint.
jeudi 19 avril 2018 21:45
• I can see that your desired output is below.

So The value of X should remain same.

But you had mentioned that,"My calculation: 4637017 (GroupShape X) + 5863712 (target ChildShape) = 10500729, but that calculation is incorrect, because when I added separate shape with this X (10500729) coordinate I see their located are different."

If you want to add textbox on same X axis then you need not to add anything. you just need to use same value of X.

For an example, Here I am using Paint to show you the coordinates in real time.

I added one line and at the both end I added a triangle.

So assume that your 2 shapes are those 2 triangles.

So you will notice that when I check the coordinates then value of X is same for both end.

So you also not need to change the value of X to add other shape in same line.

Then I again check your actual output and it looks like it is working correctly.

Regards

Deepak

MSDN Community Support
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vendredi 20 avril 2018 09:25
• Is your issue is solved now?

I find that you did not done any follow up for a long time.

If your issue is fixed by you then I suggest you to post your solution and mark it as an answer.

If your issue is still exist then try to refer the suggestions given by the community members.

If you think that the suggestions given by the community member can solve your issue then mark the helpful suggestion as an answer.

It will help us to close this thread and it also can be helpful to other community members who will meet with same kind of issues in future.

If you have any further questions then you can let us know about it, We will try to provide you further suggestions to solve it.

I suggest you to update the status of this thread and take appropriate actions to close it.

Regards

Deepak

MSDN Community Support
Please remember to click "Mark as Answer" the responses that resolved your issue, and to click "Unmark as Answer" if not. This can be beneficial to other community members reading this thread. If you have any compliments or complaints to MSDN Support, feel free to contact MSDNFSF@microsoft.com.

mercredi 2 mai 2018 09:51
• I solved this task. All right, if we wanna to calculate absolutely position child shape on the slide to do that we can use following formula:

absChildShapeOffset,x(y) =  childShapeOffset,x(y) + groupShapeOffset,x(y) - childShapeOffset,x(y)

samedi 5 mai 2018 12:26