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What is mean by this in C# x = y ^ x ^x; RRS feed

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  • Hi,

    the ^ is the xor operator.
    All C# Operators can be found at http://msdn.microsoft.com/en-us/library/6a71f45d.aspx
    The ^ operator can be found at http://msdn.microsoft.com/en-us/library/zkacc7k1.aspx

    And that expression does not make sense in my eyes: x ^ x is always 0. So you have y ^ 0 which is simply y inverted.

    a ^ b =  (a^b)
    0 ^ 0 = 0
    0 ^ 1 = 1
    1 ^ 0 = 1
    1 ^ 1 = 0

    With kind regards,

    Konrad

    Friday, September 3, 2010 1:39 PM
  • Hi,

    And that expression does not make sense in my eyes: x ^ x is always 0. So you have y ^ 0 which is simply y inverted.

    you almost got it right, if you look at your table you'll see that 0^0 = 0 and 1^0 = 1 so y^0 = y. not y inverted, the formulat still doesn't make sense though :)
    Friday, September 3, 2010 2:19 PM
  • Ahh yes, You are right of course. Thank you for the correction!
    Friday, September 3, 2010 2:22 PM
  • the formulat still doesn't make sense though :)

    Unless the operator is overloaded. We don't know what types are x and y.
    Friday, September 3, 2010 2:54 PM
  • given the topic starter had no idea what ^ did, the odds of him having overloaded the operator, rather small but hey definitly not zero could be someone elses code.
    Friday, September 3, 2010 3:33 PM
  • Hi Jaiganesh.sve,

     

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    Have a nice day!

    Mike

    Tuesday, September 7, 2010 10:56 AM
    Moderator