need display user list (with their details ) by filtering their department from active directory

Question

User456628452 posted

hi, i need display user list (with their details ) by filtering their department from active directory, from the code i have written it only retrieves single user.

i want to generate user list by filtering their departments. i didnt know how to retrieve all the department list and users listed in the department.

public ActionResult Index()
        {
            var username = User.Identity.Name;


            using (var context = new PrincipalContext(ContextType.Domain, "mydomainname"))
            {
                var user = UserPrincipal.FindByIdentity(context, username);
                if (user.GetUnderlyingObjectType() == typeof(DirectoryEntry))
                {
                    using (var entry = (DirectoryEntry)user.GetUnderlyingObject())
                    {
                        if (entry.Properties["DisplayName"] != null)
                            ViewBag.UserName = entry.Properties["DisplayName"].Value.ToString();

                        ViewBag.Email = user.EmailAddress;


                        if (entry.Properties["TelephoneNumber"] != null)
                            ViewBag.InterCom = entry.Properties["TelephoneNumber"].Value.ToString();

                        if (entry.Properties["Mobile"] != null)
                            ViewBag.MobileNo = entry.Properties["Mobile"].Value.ToString();



                        if (entry.Properties["Title"] != null)
                            ViewBag.JobTitle = entry.Properties["Title"].Value.ToString();



                        if (entry.Properties["Department"] != null)
                            ViewBag.Department = entry.Properties["Department"].Value.ToString();

                        if (entry.Properties["Company"] != null)
                            ViewBag.Company = entry.Properties["Company"].Value.ToString();
                     
                    }
                }


            }

            return View();

        }