Input string was not in a correct format.

Question

hi, anyone who can help me, when i build my project it is succeeded but when i run it and put some value it has an error pointing to this line.

                    Xrm.new_businesspermit bp = con.FindBP(con.CreateApplicant(this.txtDTI.Text, this.txtReference.Text, this.txtTIN.Text, this.txtCTC.Text, this.txtentity.Text, Int32.Parse (this.ddltypeofpermit.SelectedValue), Int32.Parse (this.ddlOwnership.SelectedValue), Int32.Parse(this.ddlpayment.SelectedValue), Int32.Parse(this.ddlamendments.SelectedValue), Int32.Parse(this.ddlTypeOfOrg.SelectedValue)));

and the error is "Input string was not in a correct format."

hope someone can help me on this . 

thanks 

Answer 1

there is an Int32.Parse that receive a value that is not an integer...probably a null string

for example the folowing code throws the same error

class Program
    {
        static void Main(string[] args)
        {
            var myval = "";
            int.Parse(myval);
        }
    }

Hope this helps.

Answer 2

Hi twinkle0903,

 

 If you don't want compile environment to prompt so unamiable message to you,you can refer to int.TryParse for more secure conversation.For more information,you can read the following link :

http://msdn.microsoft.com/en-us/library/f02979c7.aspx

 

 

Sincerely,

Jason Wang

 

Answer 3

check your string is not null when you convert to int. other wise use use parse method.

http://www.java-forums.org/forum.php

Answer 4

 your error was most likely caused because the string was empty or contained something not numeric (letter or special char)

The best way imo to convert a string to an int would be as followed :

 

string number  = "555";
int convertednumber;

if(int.TryParse(number,out convertednumber))
{
    //Handle Succes
}
else 
{
    // Failed to convert
   // Handle fail
}