How to calculate the difference count between two sequential alphanumeric 13 characters serial numbers 234CFG03DQ101, 234CFG03DQ106 =5

Question

User-695697013 posted

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How to calculate the difference count between two sequential alphanumeric 13 characters serial numbers 234CFG03DQ101, 234CFG03DQ106 =5 using JavaScript<br>

Answer 1

User2103319870 posted

How to calculate the difference count between two sequential alphanumeric 13 characters serial numbers 234CFG03DQ101, 234CFG03DQ106 =5 using JavaScript

if you have numbers always in the format i.e last 3 will be of numbers then you can use below code to calculate the differernce

var alphanum1 = "234CFG03DQ101";
//Get the last 3 digits
var num1 = alphanum1.slice(-3);

var alphanum2 = "234CFG03DQ106";
//Get the last 3 digits
var num2 = alphanum2.slice(-3);
//Calculate difference
var result = parseInt(num2) - parseInt(num1);
alert(result);

• Sample Demo

Answer 2

User-1838255255 posted

Hi balasv,

According to your description and needs, i make a sample use javascript, these are the steps of how to achieve this goal: 

1. Get all numbers from the 13 characters. 
2. Then use Math.abs to get the value of |a-b|. 

For more details, please check the following sample code:

 <script>
        debugger;
        var data1 = "234CFG03DQ101";
        var data2 = "234CFG03DQ106";

        var newdata1 = "";
        var newdata2 = "";

        for (var i = 0; i < data1.length; i++) {
            if (isNaN(data1[i])) {
            } else {
                newdata1 += data1[i]
            }
        }

        for (var i = 0; i < data2.length; i++) {
            if (isNaN(data2[i])) {
            } else {
                newdata2 += data2[i]
            }
        }

        var amount = 0;
        for (var i = 0; i < newdata1.length; i++) {
            var data = Math.abs(newdata1[i] - newdata2[i]);
            amount += data;
        }
        alert("Difference Count is: " + amount);
</script>

Best Regards,

Eric Du 

Answer 3

User-695697013 posted

Thanks, A2H   the Alphanumeric series  can have any number digits. I used the match  js function to grep me all last digts....

var alphanum1 = "234CFG03DQ101";
//Get the last 3 digits
var num1 = alphanum1.match("[0-9]+$");

var alphanum2 = "234CFG03DQ106";
//Get the last 3 digits
var num2 = alphanum2.match("[0-9]+$");
//Calculate difference
var result = parseInt(num2) - parseInt(num1);
alert(result);

Sample link