How can I create simple button to save an image

Question

Hello, How can I create simple button to save an image using print screen in my app C# windows store

her is an example http://code.msdn.microsoft.com/CSWin8AppCropBitmap-52fa1ad7

I want the same but I don't want the user to have the access to change the region

I just want him to save it with out changing the region , because I will give a specific region for the image that will not be change

thank u :)

Answer 1

You can use the SaveCroppedBitmapAsync method from that sample and pass in your own region. Just bypass the choose part of the sample.

Answer 2

You can use the SaveCroppedBitmapAsync method from that sample and pass in your own region. Just bypass the choose part of the sample.

Exactly , but I don't know how to do it , I'm a beginner

Answer 3

I could be wrong but i believe it might work for you :)

Use render target Bitmap 

private async void Snapshot_Click(object sender, RoutedEventArgs e)
{
    await CaptureAndSave(this);
}

async System.Threading.Tasks.Task<Windows.Storage.StorageFile> CaptureAndSave(UIElement element)
{
    // capture
    var bitmap = new Windows.UI.Xaml.Media.Imaging.RenderTargetBitmap();
    await bitmap.RenderAsync(element);
    var picker = new Windows.Storage.Pickers.FileSavePicker
    {
        SuggestedStartLocation = Windows.Storage.Pickers.PickerLocationId.PicturesLibrary,
        FileTypeChoices = { { "JPEG", new[] { ".jpg" } } },
        SuggestedFileName = "Image",
        DefaultFileExtension = ".jpg",
        CommitButtonText = "Save",
    };

    // save
    var file = await picker.PickSaveFileAsync();
    using (var stream = await file.OpenStreamForWriteAsync())
    {

        var pixel = await bitmap.GetPixelsAsync();
        var dpi = Windows.Graphics.Display.DisplayInformation.GetForCurrentView().LogicalDpi;
        var random = stream.AsRandomAccessStream();
        var jpg = Windows.Graphics.Imaging.BitmapEncoder.JpegEncoderId;
        var encoder = await Windows.Graphics.Imaging.BitmapEncoder.CreateAsync(jpg, random);
        var format = Windows.Graphics.Imaging.BitmapPixelFormat.Bgra8;
        var alpha = Windows.Graphics.Imaging.BitmapAlphaMode.Ignore;
        var width = (uint)bitmap.PixelWidth;
        var height = (uint)bitmap.PixelHeight;
        encoder.SetPixelData(format, alpha, width, height, dpi, dpi, pixel.ToArray());
        await encoder.FlushAsync();
    }
    return file;
}

Regards , 

hope it works for you

---

Microsoft Student Partner

Answer 4

I could be wrong but i believe it might work for you :)

Use render target Bitmap 

private async void Snapshot_Click(object sender, RoutedEventArgs e)
{
    await CaptureAndSave(this);
}

async System.Threading.Tasks.Task<Windows.Storage.StorageFile> CaptureAndSave(UIElement element)
{
    // capture
    var bitmap = new Windows.UI.Xaml.Media.Imaging.RenderTargetBitmap();
    await bitmap.RenderAsync(element);
    var picker = new Windows.Storage.Pickers.FileSavePicker
    {
        SuggestedStartLocation = Windows.Storage.Pickers.PickerLocationId.PicturesLibrary,
        FileTypeChoices = { { "JPEG", new[] { ".jpg" } } },
        SuggestedFileName = "Image",
        DefaultFileExtension = ".jpg",
        CommitButtonText = "Save",
    };

    // save
    var file = await picker.PickSaveFileAsync();
    using (var stream = await file.OpenStreamForWriteAsync())
    {

        var pixel = await bitmap.GetPixelsAsync();
        var dpi = Windows.Graphics.Display.DisplayInformation.GetForCurrentView().LogicalDpi;
        var random = stream.AsRandomAccessStream();
        var jpg = Windows.Graphics.Imaging.BitmapEncoder.JpegEncoderId;
        var encoder = await Windows.Graphics.Imaging.BitmapEncoder.CreateAsync(jpg, random);
        var format = Windows.Graphics.Imaging.BitmapPixelFormat.Bgra8;
        var alpha = Windows.Graphics.Imaging.BitmapAlphaMode.Ignore;
        var width = (uint)bitmap.PixelWidth;
        var height = (uint)bitmap.PixelHeight;
        encoder.SetPixelData(format, alpha, width, height, dpi, dpi, pixel.ToArray());
        await encoder.FlushAsync();
    }
    return file;
}

Regards , 

hope it works for you

---

Microsoft Student Partner

u r the best, thanks a lot :)

small question again , if I want a specific part of the screen , how I do it ?

I mean how should I do the points to take this position ?

I don't need to print all screen, I only need part of it .

thanks again :)