User1918509225 posted
Hi krishore13,
Thanks for your post here.
For your problem, I am not sure what the property in your class BrokertoRK .
So I wrote a demo for you.
In my sample ,I have a class Employee .
I have create two method one is used to return xml format ,the other is used to return json format.
Employee.cs:
public class Employee
{
public string Name { get; set; }
public string Company { get; set; }
public string Address { get; set; }
public string Phone { get; set; }
public string Country { get; set; }
}
Web Service.asmx:
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Xml)]
public List<Employee> TestXML()
{
List<Employee> e = new List<Employee>();
// Employee[] e = new Employee[2];
Employee e1 = new Employee();
e1.Name = "Ajay Singh";
e1.Company = "Birlasoft Ltd.";
e1.Address = "LosAngeles California";
e1.Phone = "310-235-1535";
e1.Country = "US";
Employee e2 = new Employee();
e2.Name = "Ajay Singh";
e2.Company = "Birlasoft Ltd.";
e2.Address = "D-195 Sector Noida";
e2.Phone = "120-467500";
e2.Country = "India";
e.Add(e1);
e.Add(e2);
return e;
}
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public string TestJSON()
{
Employee[] e = new Employee[2];
e[0] = new Employee();
e[0].Name = "Ajay Singh";
e[0].Company = "Birlasoft Ltd.";
e[0].Address = "LosAngeles California";
e[0].Phone = "1204675";
e[0].Country = "US";
e[1] = new Employee();
e[1].Name = "Ajay Singh";
e[1].Company = "Birlasoft Ltd.";
e[1].Address = "D-195 Sector Noida";
e[1].Phone = "1204675";
e[1].Country = "India";
return new JavaScriptSerializer().Serialize(e);
}
When you view the web service in browser , click on the TestXML button,you will see the result is in xm format.
Hope it can help you.
Best Regards,
Kevin Shen.
