how to (pass) send form value(textbox and radio button) to controller==>(save $ show in new view)

Question

User1928394251 posted

my form:

@using (Html.BeginForm("save", "modiran", FormMethod.Post, null))

{

@Html.AntiForgeryToken()
// <label>id=</label>
// <input type="text" />
<label>name=</label>
<input type="text" />
<label>modirkol</label>
<input type="radio" name="semat" value="modirkol" asp-for="input.semat" />
<label>ghaemmagham</label>
<input type="radio" name="semat" value="moaven" asp-for="input.semat" />
<label>modir</label>
<button type="submit" value="insert" title="ذخیره"> ذخیره </button>
}

=================my controller : i

public ActionResult save(FormCollection frm )
{
var model = new modiran();
var semat = Request.Form["semat"];
// var frm=db.modiran.
TryUpdateModel(model, frm);
TempData["modiran_id"] = model.modiran_id;
TempData["modiran_name"] = model.modiran_name;
// if (semat==0) then
return View();
}

my new view:

<div class="form-horizontal">
<div class="panel panel-body">
<div style="direction:rtl !important;margin:40px auto;width:70%">

<div class="form-group">

نام :

<div class="col-md-10">

@Html.TextBox("modiran_name", (string)ViewBag.modiran_name, new { @style = "width: 300px;" })

</div>
</div>
<div class="form-group">

سمت :

<div class="col-md-10">

@Html.TextBox("modiran_semat", (string)ViewBag.modiran_semat, new { @style = "width: 300px;" })

</div>

</div>>
</div>
</div>

help me please

my new view: ???????i

Answer 1

User-474980206 posted

the browser posts back enabled named form elements as name/value pairs. in the case of checkbox or radio, only the selected values are posted. your form only has 2 named elements, which are the radio buttons named seat. so the line:

   var semat = Request.Form["semat"];

the variable will set to the postbox model. you don't show the  model, but if it has a property named "semat", the line:
 
   TryUpdateModel(model, frm);

will be set, but all other properties will be null, or the default value for value types. as neither "modiran_id" nor "modiran_name" are included in the post data, the first will be zero (if a number) and the second will be null.

Answer 2

User1928394251 posted

hello.thank you .

my view is :

@using (Html.BeginForm("save", "modiran", FormMethod.Post, null))

{

@Html.AntiForgeryToken()
// <label>id=</label>
// <input type="text" />
<label>name=</label>
<input type="text" />
<label>modirkol</label>
<input type="radio" name="semat" value="modirkol" asp-for="input.semat" />
<label>ghaemmagham</label>
<input type="radio" name="semat" value="moaven" asp-for="input.semat" />
<label>modir</label>
<button type="submit" value="insert" title="ذخیره"> ذخیره </button>
}

i want to save in db and show in new view.

my controller is :

public ActionResult save([Bind(Include = "modiran_id,modiran_name,modiran_semat")] modiran model )
{
// var model = new modiran();
var semat = Request.Form["semat"];
// var frm=db.modiran.
TryUpdateModel(model, semat);
// TempData["modiran_id"] = model.modiran_id;
// TempData["modiran_name"] = model.modiran_name;
// if (semat==0) then

// TempData["modiran_semat"] = model.modiran_semat;
// TempData["modiran_semat"] = semat.Trim("modirkol");
return RedirectToAction("Index_savemodiran1");
// return View();

}

in my new view feilds is empty and dont save in my table sorry .

please help me . thanks .

Answer 3

User453055610 posted

You can set Object in javacsript send controller