Small Basic

Question

Hey i'm having trouble with a certain part of the Small Basic Curriculum, i cant figure out how to write a program that calculates the area and circumference of a circle based on its diameter. Can anyone help me understand what to do?

Thanks, ScikoticRage

Answer 1

Ok, i will explain this as best i can.

Ask the user for the diameter of the circle. then, to find the circumference, use this:

You could go:

circum = 3.14 * diameter (or what ever you name the variables)

Then,Find the area:

area = 3.14 * (diameter / 2)

(note, i used parentheses to that it wouldn't go like 3.14 * diameter then that answer divided by 2.

code:

TextWindow.WriteLine("Enter in the diameter of a circle: ")
diameter = TextWindow.Read()
circum = 3.14 * diameter
area = 3.14 * (diameter / 2)
TextWindow.WriteLine("The area is: " + area)
TextWindow.WriteLine("The circumference is: " + circum)

Help? If it doesn't, i'll gladly re-make this and explain it. :3

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I am a 12 year old learning how to code using small basic.

Answer 2

For the area you should square the diameter/2 as:

diameter*diameter/4

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Jan [ WhTurner ] The Netherlands

Answer 3

For the area you do: A = ((d / 2) * (d / 2)) * 3.14

"D" would be the diameter

Its not "area = 3.14 * (diameter / 2)" Its radius squared times pi.

See here: http://www.mathgoodies.com/lessons/vol2/circle_area.html

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It is written: "'As surely as I live,' says the Lord, 'every knee will bow before me; every tongue will acknowledge God.'" Romans 14:11

Answer 4

oh thanks. i don't really like finding the area's and circumferences...i kinda forgot how to, so yes, thanks! 

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I am a 12 year old learning how to code using small basic.

Answer 5

So like this:

TextWindow.Write("Enter the diameter: ")
Dia = TextWindow.Read()
Area = ((Dia / 2) * (Dia / 2)) * 3.14
TextWindow.WriteLine("The area is " + Area)

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It is written: "'As surely as I live,' says the Lord, 'every knee will bow before me; every tongue will acknowledge God.'" Romans 14:11

Answer 6

This is my conclusion.
Sample of Small Basic Curriculum "The Pi Property" is

TextWindow.Write("Enter the radius of the circle:")
Radius = TextWindow.Read()
Area = Math.Pi * Math.Power(Radius, 2)
TextWindow.WriteLine("Area of the Circle is " + Area)

cf. http://social.technet.microsoft.com/wiki/contents/articles/16376.small-basic-curriculum-lesson-3-3-the-math-object.aspx

So base on diameter:

TextWindow.Write("Enter the diameter of the circle:")
Diameter = TextWindow.Read()
Radius = Diameter / 2
Area = Math.Pi * Math.Power(Radius, 2)
TextWindow.WriteLine("Area of the Circle is " + Area)
Circum = 2 * Math.Pi * Radius
TextWindow.WriteLine("Circumference of the Circle is " + Circum)

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Nonki Takahashi

Answer 7

This is my conclusion.
Sample of Small Basic Curriculum "The Pi Property" is

TextWindow.Write("Enter the radius of the circle:")
Radius = TextWindow.Read()
Area = Math.Pi * Math.Power(Radius, 2)
TextWindow.WriteLine("Area of the Circle is " + Area)

cf. http://social.technet.microsoft.com/wiki/contents/articles/16376.small-basic-curriculum-lesson-3-3-the-math-object.aspx

So base on diameter:

TextWindow.Write("Enter the diameter of the circle:")
Diameter = TextWindow.Read()
Radius = Diameter / 2
Area = Math.Pi * Math.Power(Radius, 2)
TextWindow.WriteLine("Area of the Circle is " + Area)
Circum = 2 * Math.Pi * Radius
TextWindow.WriteLine("Circumference of the Circle is " + Circum)

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Nonki Takahashi

Should we make a change to the curriculum to make it easier to understand?

Thanks!

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Ed Price (a.k.a User Ed), SQL Server Customer Program Manager (Blog, Small Basic, Wiki Ninjas, Wiki)

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