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Passing xml string to REST WCF service with additional parameters RRS feed

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    I have a WCF service method that accepts 3 parameters that are all strings and will return back some data.

     [OperationContract]
       [WebInvoke(Method = "GET", ResponseFormat = WebMessageFormat.Xml,
      RequestFormat = WebMessageFormat.Xml, UriTemplate = "MyHttpRequest/{request}/{LogonID}/{Key}")]
       string TestRequest(string request, string LogonID, string Key);

    The request string parameter is supposed to be xml. Here is an example of the input, there are additional attributes but here is a sample.

    <DateOfBirth>19000101</DateOfBirth>

    I am calling this code from client like this

     HttpWebRequest req = (HttpWebRequest)WebRequest.Create(@"https://someurl.com/LookupService.svc/MyHttpRequest/" + this.tbRequestString.Text.Trim() + "/" + this.tbLoginID.Text.Trim() + "/" + this.tbKey.Text.Trim());
     req.Method = WebRequestMethods.Http.Get;

                    string result = null;
                    using (HttpWebResponse resp = (HttpWebResponse)req.GetResponse())
                    {
                        StreamReader reader = new StreamReader(resp.GetResponseStream());
                        result = reader.ReadToEnd();
                    }
    When I attempt to construct the URI I get a "A potentially dangerous Request.Path value was detected from the client (<). " 400 Bad Request. What am I doing wrong? I cant see a way to do it, and articles on the web dont seem to help or are related to POST not GET. Any ideas?




    • Edited by spark29er Wednesday, July 29, 2015 6:27 PM
    Wednesday, July 29, 2015 5:41 PM

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    Hi spark29er,

    According to this issue.I suggest you can set "ContentType " to your client code.And I write a demo

    to test it . If the client didn't set "ContentType ", it will prompt an error is that 400 Bad Request.

    My client code shown below:

    namespace Test
{
    class Program
    {
        static void Main(string[] args)
        {           
            try
            {
                string strPost = "hello here is my test app" + "By doing this, we can try to cater"                 
                byte[] buffer = Encoding.UTF8.GetBytes(strPost);
                HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create("http://LocalHost:7789/MySericeDemo/postMostStr/" + buffer.Length);
                request.Method = "POST";
                request.ContentType = "text/plain";
                request.ContentLength = buffer.Length;
                System.IO.Stream requestStream = request.GetRequestStream();
                requestStream.Write(buffer, 0, buffer.Length);
                requestStream.Close();
                System.IO.Stream getStream = request.GetResponse().GetResponseStream();
                byte[] resultByte = new byte[200];
                getStream.Read(resultByte, 0, resultByte.Length);
                Console.WriteLine(Encoding.UTF8.GetString(resultByte));

            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.ToString());
            }
            Console.ReadLine();
        }
    }
}

    My service code shown below:

    public string postMostStr(string streamlength, Stream getStream)
        {
            try
            {
                int bylength = Convert.ToInt32(streamlength);
                byte[] resultByte = new byte[bylength];
                getStream.Read(resultByte, 0, resultByte.Length);
                Console.WriteLine(Encoding.UTF8.GetString(resultByte));
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.ToString());
            }
            Console.WriteLine("success!");
            return "success";
        }

    I hope that will be helpful to you.

    Best Regards,

    Tracy Dj


    Best Regards, Tracy Dj

    Thursday, July 30, 2015 5:53 AM