# Sum of amount for all set of number combination

• ### Question

• User-1034726716 posted

Hello SQL Experts!

I am no sql guru and I have trouble getting the result i wanted. I have tried searching the web for the solution but to no avail. :(

Here's the situation. Given, I have the following table with simple data:

ID      Number         Amount

1       123                10
2       213                20
3       321                10
4      123                 60
5      122                 30

I want to get the summary of that table by summing the Amount of numbers to result to this:

Number  Total
123          100

122          20

The first combination should display in the summary. The output above displays the Number '123' since '213' and '321' are a combination of '123'.

I appreciate any guidance. Thank you in advance. :)

Sunday, March 12, 2017 6:06 AM

• User475983607 posted

This might not be the most elegant solution but it works.  Create a function that sorts the Number then you can do a GROUP BY.

```IF OBJECT_ID (N'dbo.SortNumer', N'FN') IS NOT NULL
DROP FUNCTION dbo.SortNumer;
GO

CREATE FUNCTION dbo.SortNumer(@number INT)
RETURNS VARCHAR(100)
AS
BEGIN

DECLARE @sortnums TABLE (digit VARCHAR(1));
DECLARE @sortString VARCHAR(3) = CAST(@number AS VARCHAR(100));
DECLARE @length INT = LEN(@sortString);
DECLARE @i INT = 1;
DECLARE @sorted VARCHAR(100) = '';

WHILE (@i <= @length)
BEGIN
INSERT INTO @sortnums VALUES(SUBSTRING(@sortString,@i,1));
SET @i = @i + 1;
END;

SELECT @sorted = @sorted + digit FROM @sortnums ORDER BY digit
RETURN  @sorted
END;
GO

SELECT dbo.SortNumer(231)

```
```/*
ID      Number         Amount

1       123                10
2       213                20
3       321                10
4      123                 60
5      122                 30
*/

IF OBJECT_ID('tempdb..#Amount') IS NOT NULL
DROP TABLE #Amount

CREATE TABLE #Amount (
ID INT IDENTITY(1,1),
Number	INT,
Amount INT
)

IF OBJECT_ID('tempdb..#TempAmount') IS NOT NULL
DROP TABLE #TempAmount

CREATE TABLE #TempAmount (
ID INT,
Number	INT,
Amount INT
)

INSERT INTO #Amount(Number, Amount)
VALUES  (123, 10),
(213, 20),
(321, 10),
(123, 60),
(122, 30)

INSERT INTO #TempAmount (ID, Number, Amount)
SELECT ID, CAST(dbo.SortNumer(Number) AS INT), Amount
FROM #Amount

SELECT Number, SUM(Amount) AS Total
FROM #TempAmount
GROUP BY Number```

Results

```Number      Total
----------- -----------
122         30
123         100```

• Marked as answer by Thursday, October 7, 2021 12:00 AM
Sunday, March 12, 2017 2:30 PM
• User77042963 posted
```CREATE TABLE test (id int identity(1,1),Number INT,Amount INT)
INSERT INTO test(Number, Amount)
VALUES  (123, 10),(213, 20),(321, 10),(123, 60),(122, 30)

--select * from test

;with mycte as
(select ID, Number, Amount, substring(Cast(Number as varchar(3)), n, 1 ) splitIDs
from test  cross apply (values(1),(2),(3)) d(n)
Where n <= len(Number)
)
,mycte2 as (
SELECT t1.ID,   t1.Amount  ,t1.Number ,
STUFF( ( SELECT  distinct   ',' +  Cast(t2.splitIDs as varchar(5))
FROM mycte t2
WHERE t2.Number = t1.Number
FOR XML PATH(''), TYPE).value('.', 'varchar(max)'),1,1,'')     ids  FROM mycte t1
--WHERE rn0=1
group by  t1.ID, t1.Number  ,  t1.Amount
)

,mycte3 as (
Select Number, Sum( Amount) Over(Partition by ids) total
, Row_Number() Over( partition by ids Order by Number) rn2
from mycte2

)

Select Number,total from mycte3
WHERE rn2=1

drop table test```

• Marked as answer by Thursday, October 7, 2021 12:00 AM
Monday, March 13, 2017 7:13 PM

### All replies

• User-359936451 posted

You will need to use the GROUP BY phrase on the number field then total the Amount column.

Sample of SQL code here...

http://www.w3resource.com/sql/aggregate-functions/sum-with-group-by.php

more help...

http://www.oracle.com/technetwork/issue-archive/2013/13-jan/o13sql-1886636.html

Sunday, March 12, 2017 2:07 PM
• User475983607 posted

This might not be the most elegant solution but it works.  Create a function that sorts the Number then you can do a GROUP BY.

```IF OBJECT_ID (N'dbo.SortNumer', N'FN') IS NOT NULL
DROP FUNCTION dbo.SortNumer;
GO

CREATE FUNCTION dbo.SortNumer(@number INT)
RETURNS VARCHAR(100)
AS
BEGIN

DECLARE @sortnums TABLE (digit VARCHAR(1));
DECLARE @sortString VARCHAR(3) = CAST(@number AS VARCHAR(100));
DECLARE @length INT = LEN(@sortString);
DECLARE @i INT = 1;
DECLARE @sorted VARCHAR(100) = '';

WHILE (@i <= @length)
BEGIN
INSERT INTO @sortnums VALUES(SUBSTRING(@sortString,@i,1));
SET @i = @i + 1;
END;

SELECT @sorted = @sorted + digit FROM @sortnums ORDER BY digit
RETURN  @sorted
END;
GO

SELECT dbo.SortNumer(231)

```
```/*
ID      Number         Amount

1       123                10
2       213                20
3       321                10
4      123                 60
5      122                 30
*/

IF OBJECT_ID('tempdb..#Amount') IS NOT NULL
DROP TABLE #Amount

CREATE TABLE #Amount (
ID INT IDENTITY(1,1),
Number	INT,
Amount INT
)

IF OBJECT_ID('tempdb..#TempAmount') IS NOT NULL
DROP TABLE #TempAmount

CREATE TABLE #TempAmount (
ID INT,
Number	INT,
Amount INT
)

INSERT INTO #Amount(Number, Amount)
VALUES  (123, 10),
(213, 20),
(321, 10),
(123, 60),
(122, 30)

INSERT INTO #TempAmount (ID, Number, Amount)
SELECT ID, CAST(dbo.SortNumer(Number) AS INT), Amount
FROM #Amount

SELECT Number, SUM(Amount) AS Total
FROM #TempAmount
GROUP BY Number```

Results

```Number      Total
----------- -----------
122         30
123         100```

• Marked as answer by Thursday, October 7, 2021 12:00 AM
Sunday, March 12, 2017 2:30 PM
• User475983607 posted

You will need to use the GROUP BY phrase on the number field then total the Amount column.

Sample of SQL code here...

http://www.w3resource.com/sql/aggregate-functions/sum-with-group-by.php

more help...

http://www.oracle.com/technetwork/issue-archive/2013/13-jan/o13sql-1886636.html

Your answer is off the mark.  The OP requested a design that groups all combinations of the Number field; 123, 231, and 321.

Sunday, March 12, 2017 2:33 PM
• User-359936451 posted

That is why I suggested using the GROUP BY phrase. Not off the mark its same thing you suggested.

The links I provided show exactly the same type of solution but a bit more elegant.

And allow the user to review a few approaches to the problem to solidify their knowledge.

Sunday, March 12, 2017 2:57 PM
• User475983607 posted

#### march11

That is why I suggested using the GROUP BY phrase. Not off the mark its same thing you suggested.

The links I provided show exactly the same type of solution but a bit more elegant.

And allow the user to review a few approaches to the problem to solidify their knowledge.

You might want to re-read the OPs original question.  The basis of the problem is not GROUP BY how to group all combinations of 123, 231, and 321.  Neither of the posted links cover how to do this.

Sunday, March 12, 2017 3:00 PM
• User-359936451 posted

My mistake, it appears I miss-read.

Sunday, March 12, 2017 3:03 PM
• User-1034726716 posted

Hi Mgebhard,

You're awesome! Thanks for the detailed response. I really appreciate it. I will try this method. :)

Monday, March 13, 2017 6:30 AM
• User-1034726716 posted

You will need to use the GROUP BY phrase on the number field then total the Amount column.

Hi march11,

I appreciate your response, though that's not what i'm looking for. I know how to group data. :) My problem is to group the set of number combination in the column. I think what Mgebhard solution will work.

Thank you.

Monday, March 13, 2017 6:33 AM
• User77042963 posted
```CREATE TABLE test (id int identity(1,1),Number INT,Amount INT)
INSERT INTO test(Number, Amount)
VALUES  (123, 10),(213, 20),(321, 10),(123, 60),(122, 30)

--select * from test

;with mycte as
(select ID, Number, Amount, substring(Cast(Number as varchar(3)), n, 1 ) splitIDs
from test  cross apply (values(1),(2),(3)) d(n)
Where n <= len(Number)
)
,mycte2 as (
SELECT t1.ID,   t1.Amount  ,t1.Number ,
STUFF( ( SELECT  distinct   ',' +  Cast(t2.splitIDs as varchar(5))
FROM mycte t2
WHERE t2.Number = t1.Number
FOR XML PATH(''), TYPE).value('.', 'varchar(max)'),1,1,'')     ids  FROM mycte t1
--WHERE rn0=1
group by  t1.ID, t1.Number  ,  t1.Amount
)

,mycte3 as (
Select Number, Sum( Amount) Over(Partition by ids) total
, Row_Number() Over( partition by ids Order by Number) rn2
from mycte2

)

Select Number,total from mycte3
WHERE rn2=1

drop table test```

• Marked as answer by Thursday, October 7, 2021 12:00 AM
Monday, March 13, 2017 7:13 PM
• User-1034726716 posted

Hi Limno,

Your script works well too! Thank you for taking time on looking into this. Much appreciated! :)

Wednesday, March 15, 2017 12:58 AM