How to Get Hex string with leading zeros

Question

Hi all , 

Can any one help me to convert hex string  to Hex string with leading Zero's .

Suppose i have a character string as :-

Rawdata = 3b5b4b;

I want the output as "003b5b4b"

My condition is if hex string is less then 8 char's then it should have leading zero's 

Thsnks in Advance 

Vaibhav

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Vaibhav Mishra

Answer 1

In case of STL and outputting strings to screen try this:

    char * s = "3b5b4b";

    cout << setw(8) << setfill('0') << s << endl;

Otherwise give details.

Answer 2

I am not using the STL is there any way available to get my job done 

---

Vaibhav Mishra

Answer 3

In case of MFC try this:

    CString s1 = _T("3b5b4b");

    CString s2;

    s2.Format(_T("%08s"), s1);

Otherwise give details.

Answer 4

The C function printf also uses width and fill specifications
like the CString function in MFC:

char Rawdata[] = "3b5b4b";
printf("%s\n", Rawdata);
printf("%08s\n", Rawdata);

- Wayne