how to get string for assigned licenses from azure instead of guid

Question

User389157859 posted

i am trying to retrieve user assigned licenses from azure tenant. below is the partial view i am using to modify the "@html.displayfor " and view the list of assigned licenses in a table one after the other

@using Microsoft.Azure.ActiveDirectory.GraphClient;
@model IList<AssignedLicense>

@foreach (var assignedLicense in Model)
{
    
    var a = assignedLicense.SkuId;


    @Html.DisplayFor(al => a)
}

the code works fine, but it displays a guid instead of displaying the name of the licence 

please help

Answer 1

User1724605321 posted

Hi umangkachrani,

Subscription SKU IDs and plan IDs can be read from the tenant object. For example, performing a GET request to https://graph.windows.net/myorganization/subscribedSkus returns the subscriptions available for the tenant of the signed-in user. These are returned as SubscribedSku entities and the SKU ID can be read from the skuId property. In client library , you could firstly get the subscribedSkus information available for the tenant :

               IPagedCollection<ISubscribedSku> pagedCollection = await client.SubscribedSkus.ExecuteAsync();

                List<SubscribedSku> skulist = new List<SubscribedSku>();
                if (pagedCollection != null)
                {
                    do
                    {
                        List<ISubscribedSku> skus = pagedCollection.CurrentPage.ToList();
                        foreach (ISubscribedSku sku in skus)
                        {
                            skulist.Add((SubscribedSku)sku);
                        }
                        pagedCollection = await pagedCollection.GetNextPageAsync();
                    } while (pagedCollection != null);
                }

Then you could get the skuPartNumber property from according to the AssignedLicense of current user :

             foreach (var item in user.AssignedLicenses)
             {
                    var value = skulist.Single(x=>x.SkuId==item.SkuId).SkuPartNumber;
                    
              }

Best Regards,

Nan Yu