fileupload in a server control?

Question

User-334574633 posted

Hello,

I cant seem to get the uploaded file inside my server control dll file, first i create a controls httpupload and a button, the sends it to the client inside CreateChildControls(), question is, where do i capture the respons? What function do i override to get the actual posted file??

Below is the createchildcontrol function that i use to create the upload form for the user.

FileUpload mUpload;
Button mButton;

protected override void CreateChildControls()
{
this.Controls.Clear();

this.mUpload = new FileUpload();
this.mUpload.ID = "fileInput";
this.Controls.Add(mUpload);

this.mButton = new Button();
this.mButton.ID = "btnFileUpload";
this.mButton.Text = "Upload";
this.Controls.Add(mButton);
}

Here i need to capture the uploaded file somehow.

Patrick

Answer 1

User-627724879 posted

It is sent to the server as part of the Request Object, look at the code in the ASP.NET FileUpload control.

[Browsable(false), DesignerSerializationVisibility(DesignerSerializationVisibility.Hidden)] public HttpPostedFile PostedFile { get { if ((this.Page != null) && this.Page.IsPostBack) { return this.Context.Request.Files[this.UniqueID]; } return null; } }

Answer 2

User-16411453 posted

This works too and handles the event args

Change to protected override void OnInit() 'there is an event arg in the ()

 

 

 

Answer 3

User-334574633 posted

It is sent to the server as part of the Request Object, look at the code in the ASP.NET FileUpload control.

[Browsable(false), DesignerSerializationVisibility(DesignerSerializationVisibility.Hidden)] public HttpPostedFile PostedFile { get { if ((this.Page != null) && this.Page.IsPostBack) { return this.Context.Request.Files[this.UniqueID]; } return null; } }

This works, but only for one file upload. Is it possible to make it work for several file uploads?

protected override void OnLoad(EventArgs e)
{
  if (mUpload.HasFile)
  {
    Response.Write(mUpload.FileName + "<br />");
  }
}

If i add 1 more fileupload control and use mUpload2.HasFile, it will print the same file name as mUpload.

Patrick

Answer 4

User437720957 posted

If i add 1 more fileupload control and use mUpload2.HasFile, it will print the same file name as mUpload.

 

I think you have mistyped something, because that should work just fine.

Answer 5

User-627724879 posted

Yes it should work just fine. You see it takes the UniqueId of the FileUpload control. If you look for that you should be fine.