User-1449468620 posted
I am trying to access the zipFile response from the client side using Angular. I am having trouble figuring this out so I was wondering if it would be easier to save the zipfile to disk. I understand very little with streams. I see that the zip has been
created but I do not know how to access it from angular. How do I save the file to a specific folder? I was able to save it using a basic file saving method. The .pdfs are inside it but they are corrupted. I assume because it is from a stream and I am missing
some steps.
Angular Controller
$scope.downloadZip = function (model) {
var model = $scope.selection;
var promise = DocumentZip.save(model);
promise.$promise.then(function success(model) {
notificationFactory.success();
});
}
ApiController
[HttpPost]
[ActionName("ZipFileAction")]
public HttpResponseMessage ZipFiles([FromBody]int[] id)
{
if (id == null)
{//Required IDs were not provided
throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.BadRequest));
}
List<Document> documents = new List<Document>();
using (var context = new ApplicationDbContext())
{
foreach (int NextDocument in id)
{
Document document = context.Documents.Find(NextDocument);
if (document == null)
{
throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.NotFound));
}
documents.Add(document);
}
var streamContent = new PushStreamContent((outputStream, httpContext, transportContent) =>
{
try
{
using (var zipFile = new ZipFile())
{
foreach (var d in documents)
{
var dt = d.DocumentDate.ToString("y").Replace('/', '-').Replace(':', '-');
string fileName = String.Format("{0}-{1}-{2}.pdf", dt, d.PipeName, d.LocationAb);
zipFile.AddEntry(fileName, d.DocumentUrl);
}
zipFile.Save(outputStream); //Null Reference Exception
}
}
finally
{
outputStream.Close();
}
});
streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
streamContent.Headers.ContentDisposition.FileName = "reports.zip";
var response = new HttpResponseMessage(HttpStatusCode.OK)
{
Content = streamContent
};
return response;
}
}
Here is how I tried to save the zipfile instead of returning it in a response. It saves the zip with no errors but it is corrupted.
public HttpResponseMessage ZipFiles([FromBody]int[] id)
{
if (id == null)
{//Required IDs were not provided
throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.BadRequest));
}
List<Document> documents = new List<Document>();
using (var context = new ApplicationDbContext())
{
foreach (int NextDocument in id)
{
Document document = context.Documents.Find(NextDocument);
if (document == null)
{
throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.NotFound));
}
documents.Add(document);
}
using (var zipFile = new ZipFile())
{
foreach (var d in documents)
{
var dt = d.DocumentDate.ToString("y").Replace('/', '-').Replace(':', '-');
string fileName = String.Format("{0}-{1}-{2}.pdf", dt, d.PipeName, d.LocationAb);
zipFile.AddEntry(fileName, d.DocumentUrl);
}
var zipName = "reports.zip";
string path = Path.Combine(HttpContext.Current.Server.MapPath("~/ZipFiles/"), Path.GetFileName(zipName));
zipFile.Save(path); //Null Reference Exception
}
return new HttpResponseMessage(HttpStatusCode.OK);
}
}
Here is a screenshot of the fiddler output. not sure if it helps
Screenshot
