convert date to dd/MM/YYYY format in ajax

Question

User-1722422105 posted

Hi 

below My code in ajax shows

if (!String.prototype.parseNETDate) {
String.prototype.parseNETDate = function () {
if (this.indexOf('-') == -1) {
return new Date(parseInt(this.slice(6, 19)));
} else {
return new Date(parseInt(this.slice(6, 20)));
}
};
}

out out is  Tue Oct 10 1989 00:00:00 GMT+0530 (India Standard Time)

i want op in dd/MM/YYYY 

Answer 1

User-1716253493 posted

AFAIK, formated date is a string

string datestr = thedate.ToString("dd/MM/yyyy");

Answer 2

User-330142929 posted

Hi Sidu,

According to your description, I think you convert string to data by adding a string prototype function.

I suggest that you could achieve the function you want by adding the following function to the Date prototype.

I have made a demo, wish it is useful to you.

    <script>
        Date.prototype.Format = function (fmt) { //author: meizz   
                var o = {
                    "M+": this.getMonth() + 1,                 //MM   
                    "d+": this.getDate(),                    //dd 
                    "h+": this.getHours(),                   //hh   
                    "m+": this.getMinutes(),                 //mm   
                    "s+": this.getSeconds(),                 //ss   
                    "q+": Math.floor((this.getMonth() + 3) / 3), //qq   
                    "S": this.getMilliseconds()             //S 
                };
                if (/(y+)/.test(fmt))
                    fmt = fmt.replace(RegExp.$1, (this.getFullYear() + "").substr(4 - RegExp.$1.length));
                for (var k in o)
                    if (new RegExp("(" + k + ")").test(fmt))
                        fmt = fmt.replace(RegExp.$1, (RegExp.$1.length == 1) ? (o[k]) : (("00" + o[k]).substr(("" + o[k]).length)));
                return fmt;
            }
            var d1=new Date(2018,03,22,12,34,28).Format("dd/MM/yyyy");
            var d2=new Date(2018,03,22,12,34,28).Format("dd/MM/yyyy hh:mm:ss");
            alert(d1+"\n"+d2);
    </script>

How It works.

Please feel free to let me know, if you have any question.

Best Regards,

Abraham.