I want to create a Button dynamicly，How to align it to Grid's border,for explem Grid(3,5)'s left vertical border?

Question

I want to create a Button dynamicly，How to align it to Grid's border,for explem Grid(3,5)'s left vertical  border?

Answer 1

Here's how you create the button dynamically....Just create the button within a loop so that it could be created any number of times you want...

So just have this in a click event..

private void Grid_View_Btn_1_Click(object sender, System.Windows.RoutedEventArgs e)
{   
     Dispatcher.BeginInvoke(() => {         
     StackPanel panel = new StackPanel();
     panel.Orientation = System.Windows.Controls.Orientation.Vertical;
     int i;
     for (i=0;i<5;i++)
     {
            Button btn = new Button() { Content = "Button" };
            btn.Width=130;
            btn.Height = 66;
            // btn.Margin = new Thickness(0,0,0,0)//try this if you use grid
            //grid.Children.Add(btn);
            panel.Children.Add(btn);
     }

     grid.Children.Add(panel);

  }); } 

---

Happy Coding...

Answer 2

Iam sorry,The Grid has some rowes and columns,How to align a button to Grid(row,column)?

Answer 3

You have to adjust the margin of either the grid or the button... Or else you can easily drag the corners till you align both of them......

Answer 4

Iam sorry,The Grid has some rowes and columns,How to align a button to Grid(row,column)?

mybUTTON.SetValue(Grid.RowProperty, 1);

you can also assign grid.column, grid.rowspan and grid.columnspan the same way.

Answer 5

Use SetValue to set the row and column properties.

For this in xaml:    <Button Grid.Row="3" Grid.Column="5" />

The equivalent in C# is:

    Button btn = new Button();
    btn.SetValue(Grid.RowProperty, 3);
    btn.SetValue(Grid.ColumnProperty, 5);