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Access 2013 WebApp - How to open specified record using URL RRS feed

  • Question

  • Hello,

    I need to make url link and send it to person using SendMail. When clicking on that link, user should get to record specified in URL link.

    Is there any way to include Where or get info to macro variable from URL?

    Like: https ://**.sharepoint.com/sites/***/WebApp/default.aspx?_cdt=Table_Requests&_cdv=From_Request - is opening Table called "Table_Requests" and displays form "Form_Request". And i need to open record too.

    Thursday, July 9, 2015 10:11 AM

Answers

  • Hi lalalaas,

    >> Is there any way to include Where or get info to macro variable from URL?

    No, it is impossible. At present, the URL of Access 2013 web app only supports Tile and View parameters. You could found that the URL would change which you change from different forms or different views, but it would not change when you switch to a specified record. So, user could not go to record specified in URL link.

    If this is a feature you want to include in future versions of Access 2013 web app, please submit a feedback as picture below:

    Best Regards,

    Edward


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    Friday, July 10, 2015 6:11 AM