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concatenating all items under one group RRS feed

  • Question

  • hi,

    i have created groups in report. Now i need to concate all the items under each group with "," and display all of them in one cell itself. can it be done at report level?

    Ex:  A  - 1, A -  2, A - 3, B - 1, B - 4 , B - 5

    Expected result : A - 1,2,3 

    B - 1,4,5

    Consider A,B as groups and 1,2,3,4,5 as items under each group.

    No of items in each group will be dynamic.

    Here evry thing need to be done in report only.

    thanks.

     

     



    Thursday, February 2, 2012 3:28 PM

All replies

  • Sorry , But you can do this only at your source  !

    Likely work around which might look close would be using a matrix to achieve this .

    Row Group on Fields!CharacterFieldName.Value

    Column Group Fields!GroupItemFieldName.Value .

    Detail  data expression will be same as Column Group value expression.

    Delete Column Group ( Delete only Row) Not group .


    Rajkumar Yelugu
    Thursday, February 2, 2012 3:57 PM
  • sudeep, try this. not sure if it will work. at the group level of A or B, using this expression:

    =Fields!1stLevelGroup.Value & " - " & Join(Fields!Items.Value, ",")

    good luckkk. let me know if it work, or not.

    Thursday, February 2, 2012 4:06 PM
  • Hi sudeep Puvvadi,

    I will share a workaround with List component in Reporting Services:

    1.       Drag a list to report design surface.

    2.       Right-click the list handle, select Tablix Properties.

    3.       In Tablix Properties pane, in the DatasetName drop-down list, select the main dataset of your original table.

    4.       Right click the Details group, and click Group Properties.

    5.       In Group Properties dialog, click add to define a group for the details row.

    6.       Drag a textbox into the list with the group field as its value.

    7.       Drag a matrix right after the textbox with the field containing -1,-2,-3 etc as columns group. And then delete the first empty column, hide the Data row.

    Thanks,
    Lola


    Please remember to mark the replies as answers if they help.
    • Proposed as answer by Mae Smith Monday, February 6, 2012 3:50 AM
    Monday, February 6, 2012 1:58 AM
  • thanks lola.

    but i need all the items separated by comma(,). how to achieve this?

    thanks in advance.

    Monday, February 6, 2012 6:13 AM