File Names are not coming properly while executing Receive Pipeline from Orchestration.

Question

Hi,

We receive zip file then we have to unzip and then process all the files in zip folder based on the file name. Here we implemented custom pipeline component to unzip and executing this custom receive pipeline from the orchestration. We are able to get the files but file names are not coming properly (File names are coming same for all unzipped files (first file name is coming for all) ). Please help if you have any idea.  Thanks

Here is Unzip logic.

                                                       

public void Disassemble(Microsoft.BizTalk.Component.Interop.IPipelineContext pc, Microsoft.BizTalk.Message.Interop.IBaseMessage inmsg)
        {
            string schemaNS = "https://Smc.Imaging.BizTalk.Schemas.PropertySchema1";
            string fileNS = "http://schemas.microsoft.com/BizTalk/2003/file-properties";
            IBaseMessage Temp = inmsg;
            using (ZipFile zip = ZipFile.Read(inmsg.BodyPart.GetOriginalDataStream()))
            {
                //zip.SortEntriesBeforeSaving = true;
                foreach (ZipEntry e in zip)
                {
                    var ms = new MemoryStream();
                    IBaseMessage outMsg;
                    outMsg = pc.GetMessageFactory().CreateMessage();
                    outMsg.AddPart("Body", pc.GetMessageFactory().CreateMessagePart(), true);
                    outMsg.Context=inmsg.Context;

                    e.Extract(ms);
                    string XMLMessage = Encoding.UTF8.GetString(ms.ToArray()); 

                    MemoryStream mstemp = new System.IO.MemoryStream(
                    System.Text.Encoding.UTF8.GetBytes(XMLMessage));

                    outMsg.GetPart("Body").Data = mstemp;
                    outMsg.Context.Promote("individualFileName", schemaNS, e.FileName);

                    _msgs.Enqueue(outMsg);    
                }
            }
        }

Answer 1

The reason for the problem is pretty simple. The .Context property is a reference to a Context instance so by doing:

     outMsg.Context=inmsg.Context;

your referencing the same Context object, the one belonging to the original message, with all your new messages, that's why the result is always the first.

What you need to do is copy the values, one-by-one, to the Context instance of the new message.  See here for a sample: http://www.modhul.com/2007/03/08/custom-disassembler-component-remember-the-context-properties/

Answer 2

Hi,

Another option is to use the CloneMessageContext method on the PipelineUtil class, provided by BizTalk.

Regards,

René

Answer 3

Thanks for the reply

Can you please give example how to use CloneMessageContext  method

Answer 4

Hi Ratnak,

You will have to use following code :

outMsg.Context = PipelineUtil.CloneMessageContext(InMsg.Context);

You can go through following example:

Unzip Files in a pipeline component

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I hope this helps!!!!!!

Maheshkumar S. Tiwari|BizTalk Developer Interview Questions and Answers

http://tech-findings.blogspot.com/