Event to capture on load of app

Question

Hi,

I would like to capture the event each time the app is opened when we click on the tile. To be more specific, I need to make a server call to be updated each time a user opens the app.

For e.g.: In the Mail app, if a new mail notification comes the Inbox refreshes with the latest mail in the listing., something similar needs to be achieved.

Thanks,

Neena

Answer 1

Create an application in Visual Studio, you will see this event:

 app.onactivated = function (args) {
        if (args.detail.kind === activation.ActivationKind.launch) {
            if (args.detail.previousExecutionState !== activation.ApplicationExecutionState.terminated) {
                // TODO: This application has been newly launched. Initialize
                // your application here.

            } else {
                // TODO: This application has been reactivated from suspension.
                // Restore application state here.
            }
            args.setPromise(WinJS.UI.processAll().then(function () {
          // attach event handler to your title here for click
            }));

Also in there you can attach an event handler to respond to the header / title object click.

-Jeff

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Jeff Sanders (MSFT)

Answer 2

Thanks.

This event is triggered if the user closes the app (Alt+F4) and opens again. But if we just swap and come back, and open the app the event needs to be triggered. Is that possible?

Regards,

Neena

Answer 3

It will help me answer your problem is you can tell me why do you need this information in your app? 

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Jeff Sanders (MSFT)

Answer 4

In the app I need to get mails updated each time the user opens the app. i.e.  A snyc should happen between the server side and client side when the user opens the app.