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for each new link label prosses to do

Question
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i have this code
For Each r As DataGridViewRow In DataGridView1.Rows If r.IsNewRow = True Then Return End If Dim new_label2 As New LinkLabel With r new_label2.Text = .Cells("Link").Value.ToString new_label2.Location = New Point(a, b) new_label2.BringToFront() Me.Controls.Add(new_label2) 'a += 10 b += new_label2.Height + 10 End With Next
I have viable of DataGridView is false , I want this .
The all of new_label2 is links to open powerpoint show.
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How i can click on the first new_label2 and show me the powerpoint where the source of file is in link ???
and when click on the second new_label2 show me the powerpoint where the source of file is in link ???
Thaks ..
Shady,
Tuesday, April 9, 2013 11:48 PM
Answers
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Hi Shady,
When you make a label, please add the event handler at the same time:
For Each r As DataGridViewRow In DataGridView1.Rows If r.IsNewRow = True Then Return End If Dim new_label2 As New LinkLabel With r new_label2.Text = .Cells("Link").Value.ToString new_label2.Location = New Point(a, b) new_label2.Links.add(0,.Cells("Link").Value.ToString.length,.Cells("Link").Value.ToString)
new_label2.BringToFront() Addhandler new_label2.LinkClicked, AddressOf LableLinkClicked Me.Controls.Add(new_label2) 'a += 10 b += new_label2.Height + 10 End With Next
In the handler, you can put the link in the process.start(""): http://msdn.microsoft.com/en-us/library/system.windows.forms.linklabellinkclickedeventargs.link.aspx
And you need to set the links property in above code: http://msdn.microsoft.com/en-us/library/system.windows.forms.linklabel.links.aspx
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.
- Edited by Mike Feng Tuesday, May 14, 2013 8:30 AM Correct the code
- Marked as answer by Shady Boshra Tuesday, May 14, 2013 11:59 AM
Sunday, May 5, 2013 5:39 AM -
Hi Shady,
My bad, please try this code:
new_label2.Links.add(0,.Cells("Link").Value.ToString.length,.Cells("Link").Value.ToString)
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.- Marked as answer by Shady Boshra Tuesday, May 14, 2013 11:59 AM
Tuesday, May 14, 2013 8:29 AM -
Hi Shady,
You cannot directly use the local variable in another function.
Please try this:
Public Sub EventHandler (ByVal Sender As Sstem.Object, ByVal e As System.Windows.Forms.LinkLabelLinkClickedEventArgs) Dim ll As LinkLabel = DirectCast(sender, LinkLabel) Process.Start(ll.text) End Sub
Actually, you need to use the link data like this:
Public Sub EventHandler (ByVal Sender As Sstem.Object, ByVal e As System.Windows.Forms.LinkLabelLinkClickedEventArgs) ' Displays the appropriate link based on the value of the LinkData property of the Link object. Dim target As String = CType(e.Link.LinkData, String) ' If the value looks like a URL, navigate to it. ' Otherwise, display it in a message box. If (target IsNot Nothing) AndAlso (target.StartsWith("www")) Then System.Diagnostics.Process.Start(target) Else MessageBox.Show(("Item clicked: " + target)) End If End Sub
I hope this is clear.
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.- Marked as answer by Shady Boshra Tuesday, May 14, 2013 11:58 AM
Tuesday, May 14, 2013 11:45 AM
All replies
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Hi Shady,
You need to handle LinkLabel.LinkClicked Event, see
http://msdn.microsoft.com/en-us/library/system.windows.forms.linklabel.linkclicked.aspx
http://msdn.microsoft.com/en-us/library/f6hya464.aspx
Bob Wu
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.Wednesday, April 10, 2013 8:24 AM -
Sorry , But i can't apply this because when i write ( new_label2 ) in code out the sub where code isFor Each r As DataGridViewRow In DataGridView1.Rows If r.IsNewRow = True Then Return End If Dim new_label2 As New LinkLabel With r new_label2.Text = .Cells("Link").Value.ToString new_label2.Location = New Point(a, b) new_label2.BringToFront() Me.Controls.Add(new_label2) 'a += 10 b += new_label2.Height + 10 End With Next
Show me is not right and don't work the application
Thanks.
Shady,
Wednesday, April 10, 2013 11:35 AM -
Who can heeeeeeeeeeeelp me ??Friday, April 12, 2013 12:53 AM
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Hi Shady,
Did you add LinkLabel.LinkClicked Event handler for each LinkLabel?
http://msdn.microsoft.com/en-us/library/6yyk8z93(v=vs.90).aspx
Does the event raised when you click the link?
Could you please show us your current code and current result?
Bob Wu
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.Friday, April 12, 2013 7:11 AM -
Thanks a lot , I did put the Event handler to my code .. but i have two problems for now
My first problem : my form when show me the new_label2 as label link .. i see 5 label links .. but name of all label links is new_label2
and when i put in add handler you talk about this codeProcess.Start("")
I don't know what are i will put between ""
My second problem : If i put in ""dim o as string o = new_label2.text
show me wrong with new_label2
and anther problem is new_label2 mean alllll of label links .. and when i click on the one of them open all of process is open power point files
What's can i do now ??
Thanks ..
Shady ,Saturday, April 13, 2013 12:12 PM -
Where's the answers ?!Sunday, April 14, 2013 9:22 PM
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No one can help me please ???Tuesday, April 16, 2013 3:54 PM
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Hi Shady,
When you make a label, please add the event handler at the same time:
For Each r As DataGridViewRow In DataGridView1.Rows If r.IsNewRow = True Then Return End If Dim new_label2 As New LinkLabel With r new_label2.Text = .Cells("Link").Value.ToString new_label2.Location = New Point(a, b) new_label2.Links.add(0,.Cells("Link").Value.ToString.length,.Cells("Link").Value.ToString)
new_label2.BringToFront() Addhandler new_label2.LinkClicked, AddressOf LableLinkClicked Me.Controls.Add(new_label2) 'a += 10 b += new_label2.Height + 10 End With Next
In the handler, you can put the link in the process.start(""): http://msdn.microsoft.com/en-us/library/system.windows.forms.linklabellinkclickedeventargs.link.aspx
And you need to set the links property in above code: http://msdn.microsoft.com/en-us/library/system.windows.forms.linklabel.links.aspx
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.
- Edited by Mike Feng Tuesday, May 14, 2013 8:30 AM Correct the code
- Marked as answer by Shady Boshra Tuesday, May 14, 2013 11:59 AM
Sunday, May 5, 2013 5:39 AM -
Thanks for your wonderfully answer .. but i have 2 problem
First : I have a Error in
new_label2.Links.add(.Cells("Link").Value.ToString)
The error is " Value of type 'string' cannot be converted to ' System .Windows.Forms.LinkLabel.Link "
---------------------------Second : I don't understand what i must do by this " And you need to set the links property in above code: http://msdn.microsoft.com/en-us/library/system.windows.forms.linklabel.links.aspx "
I don't know where i must put it !!
And thanks again
Shady,,Sunday, May 12, 2013 11:29 PM -
Hi Shady,
My bad, please try this code:
new_label2.Links.add(0,.Cells("Link").Value.ToString.length,.Cells("Link").Value.ToString)
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.- Marked as answer by Shady Boshra Tuesday, May 14, 2013 11:59 AM
Tuesday, May 14, 2013 8:29 AM -
Thanks for your answer ,
But when i put this codePublic Sub EventHandler (ByVal Sender As Sstem.Object, ByVal e As System.Windows.Forms.LinkLabelLinkClickedEventArgs) Process.Start(new_label2.text) End Sub
It's say Error : " Name 'new_label2' is not declared "
Thanks Again
Shady,,Tuesday, May 14, 2013 10:09 AM -
Hi Shady,
You cannot directly use the local variable in another function.
Please try this:
Public Sub EventHandler (ByVal Sender As Sstem.Object, ByVal e As System.Windows.Forms.LinkLabelLinkClickedEventArgs) Dim ll As LinkLabel = DirectCast(sender, LinkLabel) Process.Start(ll.text) End Sub
Actually, you need to use the link data like this:
Public Sub EventHandler (ByVal Sender As Sstem.Object, ByVal e As System.Windows.Forms.LinkLabelLinkClickedEventArgs) ' Displays the appropriate link based on the value of the LinkData property of the Link object. Dim target As String = CType(e.Link.LinkData, String) ' If the value looks like a URL, navigate to it. ' Otherwise, display it in a message box. If (target IsNot Nothing) AndAlso (target.StartsWith("www")) Then System.Diagnostics.Process.Start(target) Else MessageBox.Show(("Item clicked: " + target)) End If End Sub
I hope this is clear.
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.- Marked as answer by Shady Boshra Tuesday, May 14, 2013 11:58 AM
Tuesday, May 14, 2013 11:45 AM -
Oh my god .. It's Worked .. Thank you very much
Mark As AnswerThanks again
Shady,,Tuesday, May 14, 2013 11:58 AM -
So .. I want now to remove the new_label2 from form .. When form is running
Shady ,,Tuesday, May 14, 2013 1:05 PM -
So .. I want now to remove the new_label2 from form .. When form is running
Shady ,,
Hi Shady,
So you encounter a new issue? If so, make a new thread for this question.
Thanks.
Best regards,
Mike Feng
MSDN Community Support | Feedback to us
Develop and promote your apps in Windows Store
Please remember to mark the replies as answers if they help and unmark them if they provide no help.Tuesday, May 14, 2013 1:20 PM