# How to increment int by one value

• ### Question

• User1632102518 posted

I need to increment my input integer by one value everyitme I make a call to a method .

Input:  00,01,02,03,,,,99

Output: 01,02,03....99

How to implement this logic...?

Tuesday, February 3, 2015 12:23 PM

• User2103319870 posted

For Suppose if I pass 02 as Input, then it returns 3. But I want 03 as ouput.

AFAIK you have to change the datatype from integer to string since integer dont have leading zero

Sample code with string datatype

```public string AddValue(string inputnumber)
{
//Get the passed input length
int inputlength = inputnumber.ToString().Length;

//Return the result
return result;
}```
• Marked as answer by Thursday, October 7, 2021 12:00 AM
Tuesday, February 3, 2015 12:52 PM
• User281315223 posted

@Rion, that logic doesn't return me the exact ouput.

For Suppose if I pass 02 as Input, then it returns 3. But I want 03 as ouput.

It's just because the values need to be formatted using a leading zero :

```public static string IncrementWithFormat(string s)
{
// Value to store your integer
int i;

if(Int32.TryParse(s, out i))
{
// Output an incremented version of your value
return (++i).ToString("00");
}
// It wasn't an integer, output null (or throw an error)
return null;
}```

which would just be called as :

`IncrementWithFormat("02"); // yields "03"`

You can see an example of this here.

• Marked as answer by Thursday, October 7, 2021 12:00 AM
Tuesday, February 3, 2015 3:21 PM

### All replies

• User281315223 posted

If you already have an existing integer, you could simply use either of the following notations :

```yourInteger++;
yourInteger = yourInteger + 1;```

Tuesday, February 3, 2015 12:29 PM
• User1632102518 posted

@Rion, that logic doesn't return me the exact ouput.

For Suppose if I pass 02 as Input, then it returns 3. But I want 03 as ouput.

Tuesday, February 3, 2015 12:38 PM
• User2103319870 posted

For Suppose if I pass 02 as Input, then it returns 3. But I want 03 as ouput.

AFAIK you have to change the datatype from integer to string since integer dont have leading zero

Sample code with string datatype

```public string AddValue(string inputnumber)
{
//Get the passed input length
int inputlength = inputnumber.ToString().Length;

//Return the result
return result;
}```
• Marked as answer by Thursday, October 7, 2021 12:00 AM
Tuesday, February 3, 2015 12:52 PM
• User1632102518 posted

@A2H , Thanks a lot.

Tuesday, February 3, 2015 1:39 PM
• User281315223 posted

@Rion, that logic doesn't return me the exact ouput.

For Suppose if I pass 02 as Input, then it returns 3. But I want 03 as ouput.

It's just because the values need to be formatted using a leading zero :

```public static string IncrementWithFormat(string s)
{
// Value to store your integer
int i;

if(Int32.TryParse(s, out i))
{
// Output an incremented version of your value
return (++i).ToString("00");
}
// It wasn't an integer, output null (or throw an error)
return null;
}```

which would just be called as :

`IncrementWithFormat("02"); // yields "03"`

You can see an example of this here.

• Marked as answer by Thursday, October 7, 2021 12:00 AM
Tuesday, February 3, 2015 3:21 PM