convert Node.JS webservice call to C#

Question

User-235682625 posted

Hi Folks,

I have an Node.JS script which is making a webservice call the script works great , i am looking to convert this Node.JS script to C# webservice call.

Can someone please help. Thanks in advance.

var request = require('request');
var fs = require('fs');
var url = "https://yoururl/API/v3/responseimports";
var surveyId = "SV_ePswPpv4rPD77fL";
var token="AXXXXXXXXXXXXXZZZZ";
var formData={
	surveyId:surveyId,
	file: fs.createReadStream("test.csv")
};

var options = {
	headers:{
		'content-type':'multipart/form-data',
		'X-API-TOKEN':token
	},
	method:"POST",
	url:url,
	formData: formData
};

request(options, function(error,response,body){
	if(error){
		console.log("Error" +error);
	}
	else{
		console.log(response.body);
		console.log("webservice call completed");
		console.log(response.statusCode);

	}
		
});

Answer 1

User1068175894 posted

Try this code:

    string boundary = "12345";
	var filename = "test.csv";
	var paramFileStream = File.Open(fileName, FileMode.Open, FileAccess.Read);
	
	HttpContent stringContent = new StringContent("SV_ePswPpv4rPD77fL");
    HttpContent fileStreamContent = new StreamContent(paramFileStream);
	streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data");
	streamContent.Headers.ContentDisposition.Name = "\"file\"";
	streamContent.Headers.ContentDisposition.FileName = "\"" + fileName + "\"";	
	
    using (var client = new HttpClient())
    using (var formData = new MultipartFormDataContent(boundary))
    {
        formData.Add(stringContent, "surveyId");
		formData.Headers.Remove("Content-Type");
        formData.Headers.TryAddWithoutValidation("Content-Type", "multipart/form-data; boundary=" + boundary);
        formData.Add(fileStreamContent, "file");
		
        var response = client.PostAsync(actionUrl, formData).Result;
		response.EnsureSuccessStatusCode();
		fileStreamContent.Dispose();
		paramFileStream.Dispose();
    }

Answer 2

User-235682625 posted

this will not work i am using .NET version 4.0 , i am not able to use HttpContent class.

Answer 3

User2053451246 posted

this will not work i am using .NET version 4.0 , i am not able to use HttpContent class.

You can use HttpContent in 4.0 by adding a NuGet package:

https://www.nuget.org/Packages/Microsoft.Net.Http

Answer 4

User-235682625 posted

Still needs 4.5 to install that package since it uses libraries from 4.5

Answer 5

User991499041 posted

Hi Renu,

You can refer below code snippets.

main()
{
    HttpWebRequest request;
    HttpWebResponse response = null;
    string url = "*****URL*****";
    string path = @"..\test.csv";
    Random rand = new Random();
    string contentType = "text/csv";
    byte[] header = RequestHeader(boundary,path,nameValue, contentType);
    request = (HttpWebRequest)WebRequest.Create(url);
    RequestParameters(header, path, boundary);
    response = (HttpWebResponse)request.GetResponse();
}
private byte[] RequestHeader(string boundary, string path, string nameValue, string contentType)
{
    return System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\nContent-Dis-data; name=\"" + nameValue + "\"; filename=\"" + System.IO.Path.GetFileName(path) + "\"\r\nContent-Type:" + contentType + "\r\n\r\n");
}
private void RequestParameters(byte[] header, string path, string boundary)
{
    byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n");
    request.Method = "post";
    request.KeepAlive = true;
    request.ContentType = "multipart/form-data" + boundary;
    data_stream = request.GetRequestStream();
    data_stream.Write(header, 0, header.Length);
    byte[] file_bytes = System.IO.File.ReadAllBytes(path);
    data_stream.Write(file_bytes, 0, file_bytes.Length);
    data_stream.Write(trailer, 0, trailer.Length);
    data_stream.Close();
}

Regards,

zxj