check open windows in wpf

Question

hi

i am using vs2010 c# wpf application.

i have one code for windows application i.e when i pass windows form name , it check if already open then it will reactivate , if not open then it create new object and open it. the code as given below.

but i am deveoping wpf application i want use this code but this code not working...

any body know how to convert this code to wpf?

public void NodeClick(string formName)
{
switch (formName)
{
case "frmPartMaster":
if ((partMaster = (frmPartMaster)IsFormAlreadyOpen(typeof(frmPartMaster))) == null)
{
partMaster = new frmPartMaster();
partMaster.Show(this);
}
else
{
partMaster.Activate();
partMaster.WindowState = FormWindowState.Normal;
partMaster.BringToFront();
}
break;
}
}
public static Form IsFormAlreadyOpen(Type FormType)
{
foreach (Form OpenForm in System.Windows.Forms.Application.OpenForms)
{
if (OpenForm.GetType() == FormType)
return OpenForm;
}
return null;
}

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Best Regard Naweez

Answer 1

Hi naweez,

You an use the below code in your IsFormAlreadyOpen function

        foreach(Window openWin in System.Windows.Application.Current.Windows)
         {
                 if (openWin.GetType() == winType)
                    return openWin;
         }
       Hope it helps

Please let me know if you have any further query.

Regards

Ashish

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Answer 2

thanks for reply , it's working

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Best Regard Naweez