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Hold the data into Model

Question
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User733430484 posted
Hi All,
How can I pass the Data to the Model and then show in View.
Value X and Y is decimal number.Bellow that I try to do.
somebody help me.
1.Controller
using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using System.IO; using System.Data; using System.Data.OleDb; using System.Configuration; using Calculate.Models; namespace Calculate.Controllers { public class HomeController : Controller { // GET: Home public ActionResult Index() { List<decimal> valX = new List<decimal>(); decimal d1 = 2.01m; decimal d2 = 4.02m; decimal d3 = 6.06m; decimal d4 = 8.02m; List<decimal> valY = new List<decimal>(); decimal dd1 = 10.24m; decimal dd2 = 21.12m; decimal dd3 = 31.07m; decimal dd4 = 42.04m; { valX.Add(d1); valX.Add(d2); valX.Add(d3); valX.Add(d4); valY.Add(dd1); valY.Add(dd2); valY.Add(dd3); valY.Add(dd4); List<XY> FillData = new List<XY>(); FillData.Add(valX); FillData.Add(valY); } return View(); } } }
2.Model
using System; using System.Collections.Generic; using System.ComponentModel.DataAnnotations; using System.Linq; using System.Web; namespace Calculate.Models { public class XY { public decimal X { get; set; } public decimal Y { get; set; } } }
3.View
@using Calculate.Models @Model @{ ViewBag.Title = "Index"; } <h2>Index</h2> <!DOCTYPE html> <html> <body> } @if (Model.Count() > 0) { <hr /> <table cellpadding="0" cellspacing="0"> @foreach (XY data in Model) { <tr> <td>@data.X</td> <td>@data.Y</td> </tr> } </table> } </body> </html>
Thank.
Friday, May 29, 2020 4:20 AM
Answers
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User1686398519 posted
Hi, sy_60
- I modified your code according to your needs, please refer to it.
- For more information on how to bind the model, you can refer to the two links: link1,link2.
Controller
public ActionResult Index() { List<XY> FillDatalist = new List<XY> { new XY{X=2.01m,Y=10.24m}, new XY{X=4.02m,Y=21.12m}, new XY{X=6.06m,Y=31.07m}, new XY{X=8.02m,Y=42.04m} }; return View(FillDatalist); }
Index
@model IEnumerable<WebApplication1.Models.XY> @if (Model.Count() > 0) { <hr /> <table class="table"> @foreach (var item in Model) { <tr> <td>@item.X</td> <td>@item.Y</td> </tr> } </table> }
Here is the result.
Best Regards,YihuiSun
- Marked as answer by Anonymous Thursday, October 7, 2021 12:00 AM
Friday, May 29, 2020 6:11 AM
All replies
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User1686398519 posted
Hi, sy_60
- I modified your code according to your needs, please refer to it.
- For more information on how to bind the model, you can refer to the two links: link1,link2.
Controller
public ActionResult Index() { List<XY> FillDatalist = new List<XY> { new XY{X=2.01m,Y=10.24m}, new XY{X=4.02m,Y=21.12m}, new XY{X=6.06m,Y=31.07m}, new XY{X=8.02m,Y=42.04m} }; return View(FillDatalist); }
Index
@model IEnumerable<WebApplication1.Models.XY> @if (Model.Count() > 0) { <hr /> <table class="table"> @foreach (var item in Model) { <tr> <td>@item.X</td> <td>@item.Y</td> </tr> } </table> }
Here is the result.
Best Regards,YihuiSun
- Marked as answer by Anonymous Thursday, October 7, 2021 12:00 AM
Friday, May 29, 2020 6:11 AM -
User733430484 posted
Thank you very ,very much YuhuiSun,
code working.
Friday, May 29, 2020 1:56 PM