# how to generate a list of Double values if input specifed Min and Max

• ### Question

• Hello

I want know how to generate a list of Double values if input specifed Min and Max

Example Min = 2.0

Max= 10.00

Double list with 2.0, 3.0,4.0,5.0,6.0,7.0,8.0,9.0,10.0

```public static IEnumerable<double> GetDoublevalueswithinthisRange(double min, double max, double step)
{
double i;
for (i = min; i <= max; i += step)
yield return i;

if (i != max + step) // added only because you want max to be returned as last item
yield return max;
}```

this will return a value of integers in it not double for example

2,3,4,5,6,7,8,9,10

can i know why its not format with 2.0 3.0,4.0,5.0....

any alternate solution  simple would be great :)

thanks

Ranjith

Ranjith@Learner @Microsoft products

Wednesday, July 6, 2016 8:48 PM

• Hi Ranjith

>> "can i know why its not format with 2.0 3.0,4.0,5.0.... "

Because your double variable will remove 0 at the end automatically. If it is not 0, it will display properly. The following methods to show double value in the specified string format for your reference.

```string str1 = String.Format("{0:N1}",56789); //result: 56,789.0

string str2 = String.Format("{0:N2}",56789); //result: 56,789.00

string str3 = String.Format("{0:N3}",56789); //result: 56,789.000

string str8 = String.Format("{0:F1}",56789); //result: 56789.0

string str9 = String.Format("{0:F2}",56789); //result: 56789.00
```

You can try the following code and you will understand it.

```static void Main(string[] args)
{
IEnumerable<double> ie = GetDoublevalueswithinthisRange(1.0, 10.0, 1.0);
IEnumerable<double> ie2 = GetDoublevalueswithinthisRange(1.56, 10.0, 1.0);
StringBuilder sb = new StringBuilder();
foreach (double item in ie)
{
sb.Append(item.ToString("0.0") + ", ");
}
Console.WriteLine(sb);
Console.WriteLine("--------------------");
Console.WriteLine(string.Join(", ", ie));
Console.WriteLine("--------------------");
Console.WriteLine(string.Join(", ", ie2));

}

public static IEnumerable<double> GetDoublevalueswithinthisRange(double min, double max, double step)
{
double i;
for (i = min; i <= max; i += step)
yield return Math.Round(i, 1);

if (i != max + step) // added only because you want max to be returned as last item
yield return Math.Round(max, 1);
}```

Best Regards,
Li Wang

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