how to generate a list of Double values if input specifed Min and Max RRS feed

  • Question

  • Hello 

    I want know how to generate a list of Double values if input specifed Min and Max 

    Example Min = 2.0

    Max= 10.00

    Double list with 2.0, 3.0,4.0,5.0,6.0,7.0,8.0,9.0,10.0

    public static IEnumerable<double> GetDoublevalueswithinthisRange(double min, double max, double step)
               double i;
               for (i = min; i <= max; i += step)
                   yield return i;
               if (i != max + step) // added only because you want max to be returned as last item
                   yield return max;

    this will return a value of integers in it not double for example 


    can i know why its not format with 2.0 3.0,4.0,5.0.... 

    any alternate solution  simple would be great :)  




    Ranjith@Learner @Microsoft products

    Wednesday, July 6, 2016 8:48 PM


  • Hi Ranjith

    >> "can i know why its not format with 2.0 3.0,4.0,5.0.... "

    Because your double variable will remove 0 at the end automatically. If it is not 0, it will display properly. The following methods to show double value in the specified string format for your reference.

    string str1 = String.Format("{0:N1}",56789); //result: 56,789.0 
    string str2 = String.Format("{0:N2}",56789); //result: 56,789.00 
    string str3 = String.Format("{0:N3}",56789); //result: 56,789.000 
    string str8 = String.Format("{0:F1}",56789); //result: 56789.0 
    string str9 = String.Format("{0:F2}",56789); //result: 56789.00 

    You can try the following code and you will understand it.

    static void Main(string[] args)
        IEnumerable<double> ie = GetDoublevalueswithinthisRange(1.0, 10.0, 1.0);
        IEnumerable<double> ie2 = GetDoublevalueswithinthisRange(1.56, 10.0, 1.0);
        StringBuilder sb = new StringBuilder();
        foreach (double item in ie)
            sb.Append(item.ToString("0.0") + ", ");
        Console.WriteLine(string.Join(", ", ie));
        Console.WriteLine(string.Join(", ", ie2));
    public static IEnumerable<double> GetDoublevalueswithinthisRange(double min, double max, double step)
        double i;
        for (i = min; i <= max; i += step)
            yield return Math.Round(i, 1);
        if (i != max + step) // added only because you want max to be returned as last item
            yield return Math.Round(max, 1);

    Best Regards,
    Li Wang

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    Thursday, July 7, 2016 8:46 AM