What's the difference between these two?

Question

unsigned long mileage = 5UL;
unsigned long mileage = 5;

Answer 1

There is no practical difference.

Answer 2

But what about:
float v = 10;
float f = 10f;

the book I'm reading says that if you don't append the f with the literal, then it will be a double. but I tested it (initializing v's value to a value higher than a float can hold) and and they are both floats.

Answer 3

A variable of any type can only hold a maximum value permitted by that type irrespective of how much it is initialized with.

---

«_Superman_»
Microsoft MVP (Visual C++)

Answer 4

Hi vTurato,

These two definition are same. The definition float f = 10f, the postfix -f is redundant and unnecessary. It always be used to type casting. For example:

void f(unsigned int x)
{
}
void f(int x){
}
f(3); // f(int x)
f(3u); // f(unsigned int x)

For more information, please see this thread with following link:

http://stackoverflow.com/questions/1273687/why-or-why-not-should-i-use-ul-to-specify-unsigned-long

Best Regards,
Nancy

---

Please remember to mark the replies as answers if they help and unmark them if they provide no help.
Welcome to the All-In-One Code Framework! If you have any feedback, please tell us.