Convert.ToDouble最大、最小值转换问题？

Question

double dbl1 = Convert.ToDouble(double.MinValue.ToString());
double dbl2 = Convert.ToDouble(double.MaxValue.ToString());
未处理 System.OverflowException
  Message="对于 Double 类型，值或者太大，或者太小。"
  Source="mscorlib"

Answer 1

double dbl = (double)Convert.ChangeType(double.MinValue.ToString(), Type.GetType("System.Double"));
也是同样错误！按照http://msdn.microsoft.com/zh-cn/library/zh1hkw6k.aspx的说明
只当value 小于 Double.MinValue 或大于 Double.MaxValue 的数字才会报OverflowException 的。为什么这里也报错呢？

Answer 2

boss

The actual min value is -1.7976931348623157E+308 but while converting this to string, this value will be rounded of to some higher value as "-1.79769313486232E+308".

so u r getting the exception avoid rounding off... by using the following code

   string min = double.MinValue.ToString("R");
   double operand1 = Convert.ToDouble(min);

 

Answer 3

Thanks!