# How do you find the vertex, the y-intercept, and symmetric point, and use these to sketch the graph given #y=5x^2-30x+31#?

##### 1 Answer

To do this we will need to perform some algebraic manipulation.

#### Explanation:

**Vertex**

To find the vertex, we need the

Doing this gives

Plugging in

Vertex location =

**Y-intercept**

The

Doing this gives

Y-intercept =

**Symmetric Point**

A quadratic equation such as this will produce a parabola, which is always symmetric about its vertex. This means that the symmetric point will be the vertex.

**Graphing**

Mark a point where the vertex is, then mark the point with the *Hint: Draw a dashed vertical line over the vertex, and show that this line is a line of symmetry.*

After you have done this, it is reasonable to sketch the parabola.