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Distinct Count Measure group RRS feed

  • Question

  • Dear Pros

    It is known that every measure with distinct count aggregate function, will have its own measure group. My question is : Can I partition this measure group, e.g. Monthly partitions, and still have correct values for the measure, when selecting a day, month, year, etc.. in the cube ?

    Regards

    Saturday, April 2, 2016 3:05 PM

Answers

  • Hi ,

    I've ran into a relevant post which can help you get an answer :)

    https://intelligentsql.wordpress.com/2014/02/11/ssas-distinctcount/


    Regards, David .

    • Marked as answer by khidir Sunday, April 3, 2016 12:19 PM
    Sunday, April 3, 2016 11:18 AM