# How do you simplify #i^28#?

##### 1 Answer

Mar 20, 2016

#### Explanation:

We will use the following:

#i^4 = i*i*i*i = i^2*i^2 = -1*-1 = 1# #a^(bc) = (a^b)^c#

With these, we have

Mar 20, 2016

We will use the following:

#i^4 = i*i*i*i = i^2*i^2 = -1*-1 = 1# #a^(bc) = (a^b)^c#

With these, we have

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