# time complexity

• ### Question

• Problem-1 What is the running time of the following function?

void Function(int n)

{

int i=1 ;

int s=1 ;

while( s <= n)

{

i++ ;

s= s+i ;

print(\*");

}

}

Friday, September 29, 2017 5:40 AM

### All replies

• The loop will run for n times, so the complexity would be

```void Function(int n)
{
int i=1 ;  // 1
int s=1 ;  // 1
while( s <= n)  //N
{
i++ ; // 1
s= s+i ; // 1
print(\*");  // 1
}
}```

(1+1)* N * (1+1+1) = 5N

Neglecting the constant value 5 the complexity would be N as loop will run N times depending on the what is the value of variable n

Hope it helps!

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Friday, September 29, 2017 11:01 AM

>>Problem-1 What is the running time of the following function?

If you want to know the running time of the Function, you could use TimeSpan.

Best Regards,

Wendy

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Friday, October 6, 2017 3:00 AM
• If you mean how many ‘*’ will be displayed, then check this formula:

int number_of_iterations = (int)Math.Floor( Math.Sqrt( 1 + 8 * n ) - 1 ) / 2;

Friday, October 6, 2017 6:17 AM
• I think this is the answering the question as the asker is asking for something otherwise known as the big-O notation.

However, there is something wrong that, the function only accept 1 input, so it does not fit the definition of linear time.

I think the correct answer is undefined, as the you cannot deduce the time required by input size, which is always 1.

Monday, October 9, 2017 8:18 AM