Hi,
danke für deine Antwort :).
Ich hoffe du kennst dich aus, ich habe ein paar Zeilen zusammen kopiert:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
HotkeyOne();
HotkeyTwo();
}
private HotKeyManager HotKeyManager = new HotKeyManager();
void HotkeyOne()
{
HotKey Hotkey1 = new HotKey();
KeysConverter conv = new KeysConverter();
Hotkey1.Key = (Key)conv.ConvertFromString("Q");
Console.WriteLine(Hotkey1.Key);
this.HotKeyManager.KeyPressed += KeyOnePressEvent;
this.HotKeyManager.Register(Hotkey1);
}
void HotkeyTwo()
{
HotKey Hotkey2 = new HotKey();
KeysConverter conv2 = new KeysConverter();
Hotkey2.Key = (Key)conv2.ConvertFromString("W");
Console.WriteLine(Hotkey2.Key);
this.HotKeyManager.KeyPressed += KeyTwoPressEvent;
this.HotKeyManager.Register(Hotkey2);
}
void KeyOnePressEvent(object sender, KeyPressedEventArgs e)
{
string IPaddress = txtIPaddress1.Text;
string Username = txtUsername.Text;
string Password = txtPassword.Text;
Process[] pp = Process.GetProcessesByName("vlc");
foreach (Process p in pp)
{
p.Kill();
}
OpenStream(IPaddress, Username, Password);
}
void KeyTwoPressEvent(object sender, KeyPressedEventArgs e)
{
string IPaddress = txtIPaddress2.Text;
string Username = txtUsername.Text;
string Password = txtPassword.Text;
Process[] pp = Process.GetProcessesByName("vlc");
foreach (Process p in pp)
{
p.Kill();
}
OpenStream(IPaddress, Username, Password);
}
private async void OpenStream(string IPaddress, string Username, string Password)
{
if (IPaddress != "")
{
string parameter = ($" --no-video-deco --no-embedded-video --video-x=0 --video-y=0 --loop --qt-start-minimized --no-video-title-show --zoom 0.75 rtsp://{Username}:{Password}@{IPaddress}");
Process.Start(@"E:\Software\VLC\vlc.exe", parameter);
}
else
{
}
}
Fürs Verständnis:
Die beiden Hotkeys, indem Fall Numpad7 und Substract, sollen jeweils den Stream der zugewiesenen IP-Adresse
öffnen. Nur wird leider immer nur der Stream der IP-Adresse die in der letzten Textbox steht geöffnet.
Danke!
