Determining Debug/Release mode

Question

Hello,

Is it possible for the software to determine whether the code is being built in debug or release mode?  I have several testing components I only want to allow in debug mode, to help ensure people aren't using it in their components for production?

Thanks.

Answer 1

I wrotte about it in my blog, but is in spanish, although you can see the code.

 

Regards.

Answer 2

Lots of options, hope I got them all:
using System;
using System.Reflection;
using System.Diagnostics;

class Program {
  static void Main(string[] args) {
    // Compile time:
#if DEBUG
    Console.WriteLine("In debug mode");
#else
      Console.WriteLine("In release mode");
#endif
    // Run-time:
    Assembly asm = Assembly.GetExecutingAssembly();
    DebuggableAttribute attr = (DebuggableAttribute)asm.GetCustomAttributes(typeof(DebuggableAttribute), false)[0];
    if (attr.IsJITOptimizerDisabled) Console.WriteLine("In debug mode");
    else Console.WriteLine("In release mode");
    // Conditional method implementation:
    SampleClass.ThisMethodIsOnlyCalledInDebugMode(1);
    Console.ReadLine();
  }
  public static class SampleClass {
    [Conditional("DEBUG")]
    public static void ThisMethodIsOnlyCalledInDebugMode(int arg) {
      Console.WriteLine("In debug mode");
    }
  }
}

The ConditionalAttribute is sweetest of all in my book, you don't even pay for building the argument list in Release mode, it is equivalent to not programming the method call at all.  System.Diagnostics.Debug is implemented this way.

Answer 3

Hmm... great!

 

Regards.