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combobox

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  • combobox.selectedIndex.toString();
    


    Every day its a new learning. Keep Learning!!
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    Monday, January 09, 2012 12:21 PM
  • Hi
    Combobox Index Always starts with 0
    So if you select 3rd item the index is 2
    Code Snipt:

               String s;
                if( comboBox1.SelectedIndex>=0)
                {
                s = comboBox1.SelectedIndex.ToString();
                MessageBox.Show(s);
                }
    

    By
    A Pathfinder.
    Joswa

     


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    Monday, January 09, 2012 12:27 PM
  • It does not work .

    error: Cannot implicitly convert type 'string' to 'int'

    Monday, January 09, 2012 12:28 PM
  •  

    String teacherField = comboBox_tchrLevel.SelectedIndex.ToString();

    I try this but it does not work 

    Error:Cannot implicitly convert type 'string' to 'int'

    Monday, January 09, 2012 12:40 PM
  • > String teacherField = comboBox_tchrLevel.SelectedIndex.ToString();

    There is nothing in this statement that should require conversion from a string to an Integer, as the error message states. 

    Are you sure this is your actual code?

    On the off-chance that it is, put a breakpoint on the errant line, then run these in the Immediate Window - what do they return?

    ? combobox_tchrLevel.GetType().ToString()
    ? combobox_tchrLevel.SelectedIndex.GetType().ToString()
    ? combobox_tchrLevel.SelectedIndex.ToString().GetType().ToString()
    ? teacherField.GetType().ToString()



    Regards, Phill W.
    Monday, January 09, 2012 2:27 PM
  • Hi Junaid,
    According to your description, I think you used teacherField as an Int(see http://msdn.microsoft.com/en-us/library/xzhh5fx5.aspx), could you post the code which throws the error message? If you can’t find the code, please post the entire code.
    Best Regards,

    Bob Wu [MSFT]
    MSDN Community Support | Feedback to us
    Tuesday, January 10, 2012 7:11 AM
    Moderator