How to Deserialize XML String

Question

How to deserialize following string into Object of specific class.
<UserManagement>
<UserManage>
			<ActionType>1</ActionType>
			<User_ID>0</User_ID>
			<sCode>dtest12042012</sCode>
			<FirstName>dtestupdated-1</FirstName>
			<LastName>DTest</LastName>
			<Password>pune007</Password>
			<Email>[e-mail]</Email>
			<CreateBy>1269</CreateBy>
			<NodeId>1000</NodeId>
			<Max_Login_Attempt>3</Max_Login_Attempt>
			<is_New_Account_Access>0</is_New_Account_Access>
			<Notify_Login_PswFail>0</Notify_Login_PswFail>
			<Notify_Login_UserFail>0</Notify_Login_UserFail>
			<ZoneID>51</ZoneID>
			<Default_Culture_ID>1</Default_Culture_ID>
			<User_Question>Your Pet Name?</User_Question>
			<User_Answer>ddc</User_Answer>
			<Group_ID>;76;</Group_ID>
</UserManage>
<UserManage>
			<ActionType>1</ActionType>
			<User_ID>0</User_ID>
			<sCode>dtest12042012</sCode>
			<FirstName>dtestupdated-1</FirstName>
			<LastName>DTest</LastName>
			<Password>pune007</Password>
			<Email>[e-mail]</Email>
			<CreateBy>1269</CreateBy>
			<NodeId>1000</NodeId>
			<Max_Login_Attempt>3</Max_Login_Attempt>
			<is_New_Account_Access>0</is_New_Account_Access>
			<Notify_Login_PswFail>0</Notify_Login_PswFail>
			<Notify_Login_UserFail>0</Notify_Login_UserFail>
			<ZoneID>51</ZoneID>
			<Default_Culture_ID>1</Default_Culture_ID>
			<User_Question>Your Pet Name?</User_Question>
			<User_Answer>ddc</User_Answer>
			<Group_ID>;76;</Group_ID>
</UserManage>
<UserManage>
			<ActionType>1</ActionType>
			<User_ID>0</User_ID>
			<sCode>dtest12042012</sCode>
			<FirstName>dtestupdated-1</FirstName>
			<LastName>DTest</LastName>
			<Password>pune007</Password>
			<Email>[e-mail]</Email>
			<CreateBy>1269</CreateBy>
			<NodeId>1000</NodeId>
			<Max_Login_Attempt>3</Max_Login_Attempt>
			<is_New_Account_Access>0</is_New_Account_Access>
			<Notify_Login_PswFail>0</Notify_Login_PswFail>
			<Notify_Login_UserFail>0</Notify_Login_UserFail>
			<ZoneID>51</ZoneID>
			<Default_Culture_ID>1</Default_Culture_ID>
			<User_Question>Your Pet Name?</User_Question>
			<User_Answer>ddc</User_Answer>
			<Group_ID>;76;</Group_ID>
</UserManage>
</UserManagement>

Answer 1

You didnt ask a thing, so we dont actually know what would you like to do. But here is some brief explanation:

Why would you deserialitze string to object? Object can be any type. So there is no need of boxing or anything else.

Example:

string str = "abc";
int num = 1;
object obj1 = str;
object obj2 = num;

---

Mitja

Answer 2

Read Controlling XML Serialization Using Attributes.

Answer 3

use the attribute function for deserialize like -

for more refer this link-

http://stackoverflow.com/questions/364253/how-to-deserialize-xml-document

Answer 4

Hi Dhaval, 

You can also use XDocument with LINQ combination to retrieve back as objects, I will show simple example how to?

Have a class structure

  public class UserManagement
        {
            public UserManagement()
            {
                Managers = new List<UserManage>();
            }
            public List<UserManage> Managers { get; set; }
        }

        public class UserManage
        {
            public int ActionType { get; set; }
        }

 

for simplicity I just considered only property ActionType

and perform like, 

 var xml = @"<UserManagement>
<UserManage>
			<ActionType>1</ActionType>
</UserManage>
<UserManage>
			<ActionType>2</ActionType>
</UserManage>
<UserManage>
			<ActionType>3</ActionType>
</UserManage>
</UserManagement>";


  var xDoc = XDocument.Parse(xml, LoadOptions.PreserveWhitespace);
  var userManageList = from item in xDoc.Descendants("UserManage")
                       select new UserManage { ActionType = (int)item.Element("ActionType") };

  var userManagement = new UserManagement();
  userManagement.Managers.AddRange(userManageList.ToArray());

I hope this helps you..

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Answer 5

Thanks for help. But,

I need dynamic XML Deserialization ,I can't pass/write node element in string format.

I'm not able to do this ("item.Element("ActionType")"). Because, I don't know Element Name

Answer 6

Hi Dhaval,

You can generalize the implementation by using Reflection . If you provide more details like how you expect your input? How does you know which element matches to which property? ..etc

We will be able to help you...

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